Powershell - for loop with multiple conditions

Question

im trying to have a for loop which ends after 1 of 2 conditions is fullfilled.

I dont know what i am missing but with "-or" between these 2 conditions only one condition seems to be "working" i guess. Should the following for-loop not also quit after the value of $i is 3??

Here the code:

$test = "test"
$expected = "successful"
for($i = 0; ($i -lt 3) -or ($test -ne $expected); ($i++) -and (sleep 1)){
    if($i -eq 5){
        $test = $expected
    }
    $test
    $i
}

and here is my output:

test 0 test 1 test 2 test 3 test 4 successful 5

-or makes the loop continue as longer as either condition is satisfied, change the -or to an -and. — Mathias R. Jessen
– Mathias R. Jessen, Commented Mar 18, 2022 at 9:22

Mathias R. Jessen · Accepted Answer · 2022-03-18 09:28:51Z

3

Should the following for-loop not also quit after the value of $i is 3?

Why should it? ($test -ne $expected) is still $true, and you've instructed PowerShell to continue the loop as long as either ($i -lt 3) or ($test -ne $expected) are true.

Change the loop condition to use the -and operator instead:

for($i = 0; ($i -lt 3) -and ($test -ne $expected); ($i++) -and (sleep 1))

Assuming you want the sleep 1 statement to execute regardless of the value of $i, change the last part to not use -and too:

for($i = 0; ($i -lt 3) -and ($test -ne $expected); ($i++;sleep 1)){

answered Mar 18, 2022 at 9:28

Mathias R. Jessen

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1 Comment

Santiago Squarzon Over a year ago

I think it would need $(..) for the second example: $($i++;sleep 1)

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