How to generate an image randomly in python

Question

Hiii, I'm making a game in my computer science class and I need to figure out how to generate an image randomly somewhere on the screen in pygame. The game is a basically just a car moving around and you have to dodge to obstacles but i have no idea how to get my chosen obstacle randomly on the screen. this is what i have so far...

import pygame
import random

pygame.init()
myClock = pygame.time.Clock()
WIDTH = 450
HEIGHT = 450

screen = pygame.display.set_mode((WIDTH,HEIGHT))

#images
bg = pygame.image.load("roads.png")
car = pygame.image.load("barbiecar.png")
cone = pygame.image.load("cone.png")

carRect = car.get_rect()
coneRect = cone.get_rect()



bg = pygame.transform.scale(bg,(WIDTH,HEIGHT))
carRect = car.get_rect()
posX = 198
posY = 430
pos_back = 0

while True:
  carRect.center = (posX,posY)
  
  for event in pygame.event.get():
    if event.type == pygame.QUIT:
      pygame.quit()
    elif event.type == pygame.KEYDOWN:
      if event.key == pygame.K_d:
        posX=posX+7
      elif event.key == pygame.K_w:
        posY=posY-7
      elif event.key == pygame.K_a:
        posX = posX-7
      elif event.key == pygame.K_s:
        posY= posY + 7

  screen.blit(bg,(0,pos_back))
  screen.blit(bg,(0,pos_back-WIDTH))
  #screen.blit(car,(posX,posY))
  screen.blit(car,(carRect))

  if pos_back == +WIDTH:
    screen.blit(bg,(0,WIDTH+pos_back))
    pos_back = 0
  pos_back = pos_back+1
   
  
    
  pygame.display.update()
  myClock.tick(40)

Generate a valid (x, y) point to place the obstacle at. If it doesn't meet the requirements, generate it again until it does. Then draw the obstacle at the specified coordinates. — Eric Jin
– Eric Jin, Commented Apr 26, 2022 at 22:23

danangjoyoo · Accepted Answer · 2022-04-26 23:05:35Z

1

maybe you can try using random module

import random as rd
...

## then in your code
while True:
    ...
    screen.blit(my_choosen_object, (rd.randint(0, WIDTH), rd.randint(0, HEIGHT)))

answered Apr 26, 2022 at 23:05

danangjoyoo

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