jquery's ajax method

Question

$.ajax({
    type:"get",
    url:"/test/api/?u="+u,
    dataType:"json",
    data:"",
    success:function result(data){
            $("#show").html(data);
        $("#show").show();
       }
});

i don't understand the above code well, especially the success part. i don't know what will be passed to the parameter data. expect someone can explain it to me. thank you.

May I suggest reading the documentation on the $.ajax method? api.jquery.com/jQuery.ajax — Cᴏʀʏ
– Cᴏʀʏ, Commented Aug 31, 2011 at 1:25

Brian Glaz · Accepted Answer · 2011-08-31 01:22:19Z

1

data will hold the content returned by the url that you sent the request to. If the url you are posting to is another HTML page, the code for the entire page will be stored in data for example.

answered Aug 31, 2011 at 1:22

Brian Glaz

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Comments

pricco · Accepted Answer · 2011-08-31 01:34:40Z

0

In this case data is a javascript object, like a dictionary, list, int, string, etc. because the dataType is json and jQuery auto-convert the response returned by the url to a javascript object.

answered Aug 31, 2011 at 1:34

pricco

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2 Comments

Cᴏʀʏ Over a year ago

The line means: Select the element whose ID is "show" and attempt to replace its HTML content (e.g. innerHTML) with the contents of variable data. Presumably data is a string, and more specifically a string that represents HTML markup.

pricco Over a year ago

@CoryLarson +1. But it doesn't make sense to use json in this case.

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