How to echo php variable with text inside a function call?

Question

Using the thumbsup script to generate ratings for various things. Here is the current code:

echo ThumbsUp::item($reviewid)->template('mini_thumbs2')->format('{UP} out of {TOTAL} people found this review helpful')

I'm trying to add the text review_ before $reviewid. No matter what I try, Dreamweaver will stop showing errors, but the variable doesn't pass through. Last thing I tried is:

echo ThumbsUp::item('review_$reviewid')->template('mini_thumbs2')->format('{UP} out of {TOTAL} people found this review helpful')

I'd accept at least 5 of your answers to your other 6 questions... — Blender
– Blender, Commented Sep 14, 2011 at 22:58
Can you post the code for format() (from ThumbsUp::item)? — Bojangles
– Bojangles, Commented Sep 14, 2011 at 22:58

amphetamachine · Accepted Answer · 2011-09-14 23:02:14Z

3

Have you tried using double quotes? Variables (and this is the rule for Perl too) won't interpolate into strings unless you use double quotes.

//                  v- double quotes-v
echo ThumbsUp::item("review_$reviewid")->template('mini_thumbs2')->format('{UP} out of {TOTAL} people found this review helpful')

Alternatively, you could use string concatenation to do the same thing:

echo ThumbsUp::item('review_' . $reviewid)-> ...

answered Sep 14, 2011 at 23:02

amphetamachine

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Nazariy · Accepted Answer · 2011-09-14 23:04:56Z

2

I would recommend you escape variables with curly brackets, as this approach allows you to use object variables, example:

echo ThumbsUp::item("review_{$reviewid}")->template('mini_thumbs2')->format('{UP} out of {TOTAL} people found this review helpful');

answered Sep 14, 2011 at 23:04

Nazariy

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brain · Accepted Answer · 2011-09-14 23:04:10Z

0

Variables are not expanded within '', only within "".

echo ThumbsUp::item("review_$reviewid")->template('mini_thumbs2')->format('{UP} out of {TOTAL} people found this review helpful');

answered Sep 14, 2011 at 23:04

brain

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