Compare command line arguments to string in C?

Question

Compare command line arguments to strings in c? for example I want just the word "autoplay" to be the command line argument, how can i validate that this is the only word? i already have it validating for more than 1 word.

if( argc == 2 ) {
    autoplay(num5);
}

There's nothing special about command line arguments, they're just ordinary strings. Use strcmp() to compare them. if (argc == 2 && strcmp(argv[1], "autoplay") == 0) — Barmar
– Barmar, Commented Oct 28, 2022 at 19:30
How about something like for(int i = 0; i < argc; i++) if(strcmp(argv[i], "autoplay") == 0) autoplay(num5);? — Fiddling Bits
– Fiddling Bits, Commented Oct 28, 2022 at 19:30
@FiddlingBits strcmp() doesn't return a boolean, it returns 0 when the strings match. — Barmar
– Barmar, Commented Oct 28, 2022 at 19:31
if( argc == 2 ) then there only is one argument. If can therefor only be the only word. So, either your question needs more explanation, or it is already solved by the code you have shown. — Yunnosch
– Yunnosch, Commented Oct 28, 2022 at 19:34

user9706 · Accepted Answer · 2022-10-28 19:34:56Z

2

You use strcmp() to compare strings; note it returns 0 on match. If you want it case insensitive then you need to use strcasecmp() instead:

#include <stdio.h>
#include <string.h>

int main(int argc, char **argv) {
    if(argc == 2 && !strcmp(argv[1], "autoplay")) {
        printf("match\n");
        // autoplay(num5);
        return 0;
    }
    printf("no match\n");
}

and example run;

./a.out
no match
./a.out autoplay
match

answered Oct 28, 2022 at 19:34

user9706

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