Python Regex for selecting lines that follows a specific pattern [duplicate]

Question

How can I make a regex that will select lines that does not follow a pattern. So I have log file that has the following pattern:

[12.12.2022 22:26:25] <01> Info Unregistering TCP client channel [bstcp] [12.12.2022 22:26:25] <01> Info Channel successfully unregistered

but everytime a new log starts it will also log the following:

=================================================================== Starting new log Process: [64 bit], PID: [5028], SessionId: [0]

How can I select only the ones with the patter:

[date] loglevel message

Thanks

I was trying things on https://regex101.com/ but I was not successful.

I am expecting to select all the lines that has the following pattern:

[date] loglevel message

Tim Biegeleisen · Accepted Answer · 2022-12-12 23:39:16Z

1

If you just want lines starting with the date/timestamp, you should be able to just use the following regex pattern in multiline mode:

^\[\d{2}\.\d{2}\.\d{4} \d{2}:\d{2}:\d{2}\].*$

The date pattern is fairly distinct and should only match the lines you want.

Demo

answered Dec 12, 2022 at 23:39

Tim Biegeleisen

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