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I have a dataset that looks like this:

> dput(test)
structure(list(Apple = c(0L, 1L, 1L, 0L, 1L), Banana = c(1L, 
1L, 0L, 0L, 0L)), class = "data.frame", row.names = c(NA, -5L
))

I want to create a binary variable that signifies if either Apple and/or Banana is 1.

  • If both Apple and Banana are 0, then the value in the new variable should be 0.

  • If Apple is 1 but Banana is 0 (and vice versa), then the value in the new variable should be 1.

  • If Apple AND Banana is 1, then the value in the new variable should be 1.

This should be the output:

 dput(test)
structure(list(Apple = c(0L, 1L, 1L, 0L, 1L), Banana = c(1L, 
1L, 0L, 0L, 0L), Apple_or_Banana = c(1L, 1L, 1L, 0L, 1L)), class = "data.frame", row.names = c(NA, 
-5L))
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1

3 Answers 3

Reset to default
4 
test$Apple_or_Banana = as.numeric(test$Apple | test$Banana)

Gives the result that you are after, I think.

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4

One way:

test$Apple_or_Banana <- ifelse(rowSums(test) > 0, 1, 0)

Result:

  Apple Banana Apple_or_Banana
1     0      1               1
2     1      1               1
3     1      0               1
4     0      0               0
5     1      0               1
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1 Comment

A similar variant might be test$Apple_or_Banana <- +(rowSums(test) > 0)
0

A variant general approaches for more than two columns and also other conditions than 1 will be.

test$Apple_or_Banana <- +(apply(test==1, 1, any))

#test
#  Apple Banana Apple_or_Banana
#1     0      1               1
#2     1      1               1
#3     1      0               1
#4     0      0               0
#5     1      0               1
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