Java Xml to Object?

Question

What are the steps getting an (model) object from an XML file?

Given an XSD and JAXB dependency at Spring 3, built with Maven using Java 1.6.

Note: I am new to Spring and that technologies.

What I tried

I put that dependency (can I use a newer version):

    <dependency>
        <groupId>org.springframework.ws</groupId>
        <artifactId>spring-oxm-tiger</artifactId>
        <version>1.5.4</version>
    </dependency>

and that

        <plugin>
            <groupId>org.jvnet.jaxb2.maven2</groupId>
            <artifactId>maven-jaxb2-plugin</artifactId>
            <executions>
                <execution>
                    <id>generate-oxm</id>
                    <goals>
                        <goal>generate</goal>
                    </goals>
                    <configuration>
                        <schemaDirectory>src/main/resources/META-INF/xsd</schemaDirectory>
                        <generatePackage>com.aaa.xjc</generatePackage>
                    </configuration>
                </execution>
            </executions>
        </plugin>
        <plugin>
            <inherited>true</inherited>
            <groupId>org.apache.maven.plugins</groupId>
            <artifactId>maven-compiler-plugin</artifactId>
            <configuration>
                <source>1.6</source>
                <target>1.6</target>
            </configuration>
        </plugin>

to my POM file.

I made a class like that:

@Configuration
public class XmlAdapter {
    @Autowired
    private ResourcePatternResolver resourceResolver;

    @Bean
    public Jaxb2Marshaller oxmMarshaller() throws IOException {
        Jaxb2Marshaller marshaller = new Jaxb2Marshaller();
        marshaller.setContextPath("com.aaa.xjc");
        marshaller.setSchemas(resourceResolver.getResources("classpath:/META-INF/xsd/*.xsd"));
        return marshaller;
    }

}

Problem

Actually I didn't understand that context path and how to call that oxmMarshaller method.

How can I use my existing XSD to validate them? I tried that according to my previous question: Xml to Object java Spring 3

spring doesn't have much to do with it. Just go through a JAXB tutorial — Bozho
– Bozho, Commented Oct 10, 2011 at 20:13

smp7d · Accepted Answer · 2011-10-10 20:39:05Z

1

You will first need to run xjc on the XSD to generate the JaxB classes. You will then need to create these JaxB objects, ideally using the generated ObjectFactory. At that point you can send that object to the JaxB2Marshaller. If you want to return as a response in a web application, you can use the MarshallingView.

As far as the maven deps, all the JaxB stuff will be included with Java 6. You will need to properly manage the spring deps. At the very least, you will need Spring OXM.

answered Oct 10, 2011 at 20:39

smp7d

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John B · Accepted Answer · 2011-10-10 20:29:02Z

1

Run xjc on the schema to generate the java classes. XJC
Use the JaxB Unmarshaller to parse the file. Unmarshalling

answered Oct 10, 2011 at 20:29

John B

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