Regex in vim while doing replace

Question

I have a text file with many statements like: "1", "23",..... etc and I want to replace these occurrences with 1, 23,.... etc. That is just removing the quotes. How can I do this in VIM?

you should maybe run vimtutor.

Benoit
– Benoit

2011-10-11 09:25:54 +00:00
Commented Oct 11, 2011 at 9:25 — Benoit
– Benoit, Commented Oct 11, 2011 at 9:25

Benoit · Accepted Answer · 2011-10-11 06:44:51Z

4

Use :

:%s/"\(\d\+\)"/\1/g

Which means: replace any sequence of digits between double quotes with the sequence of digits itself.

For more reference:

:help :s
:help pattern

answered Oct 11, 2011 at 6:44

Benoit

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Ves Over a year ago

Useful example of search command, but IMHO simple s/"//g do "just removing the quotes" as requested in the question

lc2817 · Accepted Answer · 2011-10-11 06:45:06Z

2

You type esc then:

:%s/\"\([0-9]*\)\"/\1/g

This will substitute the pattern: " any digits " by any digits. Note that \1 will replicate what has been matched within these: \( \)

answered Oct 11, 2011 at 6:45

lc2817

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Benoit Over a year ago

This will also delete any pair of successive double-quotes with no digits inside.

ronakg · Accepted Answer · 2011-10-11 06:46:54Z

0

You can do it like this -

:%s/"\(\d\+\)"/\1/c

answered Oct 11, 2011 at 6:46

ronakg

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1 Comment

Benoit Over a year ago

/c will ask for confirmation, and only once per line. You at least want to add the g flag also.

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