The solution presented in Convert a string list/set to json objects in java seems not to work with javax.json.
In version 1.1.4 of the javax.json JSONObject is a subclass of the typed Map<String, JsonValue>.
Hence
jsonObject.put("key", "value")
leads to an error, because put expects now an Json Object as the second object.
However, I did not find an easy way to convert a simple String into a JsonValue.
What is the best way to create a simple JsonValue?
Wallenstein
You are wrong in that javax.json.JsonObject has changed, this is how it always worked in its immutable way. See here for more reference: https://stackoverflow.com/a/26346341/471160, this is from 2014.
Since you reference a link to SO question about jackson you probably mixed code from two different libraries. If you want code like jsonObject.put("key", "value") to work then use jackson:
// com.fasterxml.jackson.core:jackson-core:2.13.3
ObjectMapper mapper = new ObjectMapper();
ObjectNode jsonObject2 = mapper.createObjectNode();
jsonObject2.put("key", "value");
System.out.println(jsonObject2);
or org.json
// org.json:json:20230227
JSONObject jsonObject = new JSONObject();
jsonObject.put("key", "value");
System.out.println(jsonObject);
javax.json.JSONObject extends Map<String, JsonValue>
So, you need to convert your String into a JsonValue.
Try this:
JsonObject jsonObject = Json.createObjectBuilder()
.add("key", "yourValue") // "yourValue" will be handled as a JsonValue
.build();
System.out.println(jsonObject);
javax.json.JSONObject extends Map<String,JsonValue> since the first version. The jsonObject.put("key", "value") example uses Jackson, as Chaosfire already mentioned. Your answer is still a good solution though.
javax.json I think your answer is excellent. What marcinj suggest requires a different JSON library, which may require a lot of refactoring.
jackson, notjavax.json, why do you expect that solution to work?