I was trying to do something like this but i don't know much about this language:
def teste (*array1, *array2)
Is this possible to do? I have to pass one array of numbers and strings and one only of strings but i dont know how much elements each one has.
It doesn't matter how many elements both of your array arguments have. For your purpose you can do just this:
def teste(arr_of_strings_and_numbers, arr_of_only_strings)
Now call the method like this:
teste( [1, 2, 3, 'foo', 'bar'], ['foo', 'bar', 'baz'] )
In your method body you have now access to:
arr_of_strings_and_numbers which equals [1, 2, 3, 'foo', 'bar']
and
arr_of_only_strings which equals ['foo', 'bar', 'baz']
You can pass as many arguments as you need to.
You may not want to "splat"them, though, that does something pretty specific.
That's not possible, there's no way for the language to know to which array an element belongs to. However you can simply pass 2 arrays.
You can't have two variadic lists of arguments in a method. If it were legal to define a method with two variadic lists of arguments like you want to, how would ruby know which argument should go in which array when you call say teste(a,b,c)? Should this result in array1 = [a]; array2 = [b,c] or array1 = [a,b]; array2=[c]? It's impossible to say.
If you want to pass two arrays to a method, just define it to take two regular arguments and then call it with two arrays.
teste(var1, var2, var3, var4)where var1 and var2 are part of array1 and var3 and var4 are part of array2. As I said in my answer, it's not possible.