I am not able to display image using this code. Could any one help me in correcting?
<?php
include("connect.php");
$sql="select * from profile where userid=3";
$row=mysql_query($sql);
header("Content-type: image/jpeg");
echo $row['image'];
?>
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Need more information. Do you save the image as raw text in the database? And tell us, what exactly is not working.sascha– sascha2011-11-11 08:17:07 +00:00Commented Nov 11, 2011 at 8:17
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2 Answers
Try
<?php
include("connect.php");
$sql = "SELECT * FROM profile WHERE userid='3'";
$row = mysql_fetch_assoc(mysql_query($sql));
echo '<img src="'.$row['image'].'" />';
?>
Depends how your information is stored in the database. If you have stored the path to a picture, this will be the right way. If you have stored the whole picture, this must be done another way.
Comments
Have you tried this way:-
echo "<img src=\"".$row['image']."\">";
