Java String formation for ListView

Question

I have created a Java code for my Android App.

String[] MovieName=new String[]{};

for (int i = 0; i < 15; i++) 
{
MovieName[i]=movieAtt.getAttributeValue( "name" );  //Value coming from my XML
}

ListViewObject.setAdapter(new ArrayAdapter<String>(screen2.this,android.R.layout.simple_list_item_1 , MovieName));

This code throws an Exception. I think i am not inserting vaues properly inside Java String Array.

All i want is to have a variable like MovieName={"1","2", "3"} to feed into the ListView of my code.

This is not much helpful too : http://download.oracle.com/javase/6/docs/api/java/lang/String.html

Throwing which exception? Can you point it out?

Abimaran Kugathasan
– Abimaran Kugathasan

2011-11-16 07:30:13 +00:00
Commented Nov 16, 2011 at 7:30 — Abimaran Kugathasan
– Abimaran Kugathasan, Commented Nov 16, 2011 at 7:30

hage · Accepted Answer · 2011-11-16 07:30:07Z

3

You initialize an empty array.

Try this

String[] MovieName = new String[15];

answered Nov 16, 2011 at 7:30

hage

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1 Comment

typedefcoder2 Over a year ago

Working Great Guys. Wish i could add all of you three as answers.

Udo Held · Accepted Answer · 2011-11-16 07:28:12Z

3

Your initilizing an empty string array. That will give you an ArrayOutOfBoundException.

If you always have 15 entries you could initialize it to 15.

String[] MovieName=new String[15];

Otherwise you could create an ArrayList and convert it to an array after you filled it.

answered Nov 16, 2011 at 7:28

Udo Held

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Comments

Vladimir · Accepted Answer · 2011-11-16 07:29:37Z

1

If number of elements in MovieName is constant, then you should initialise it as

String[] MovieName=new String[15];

Your current initialisation is equal to

String[] MovieName=new String[0];

answered Nov 16, 2011 at 7:29

Vladimir

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1 Comment

typedefcoder2 Over a year ago

I have a variable, that gives me children of XML. for that variable i need to run the loop. Trying it. Thanks.

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