How to write a trigger function to Jquery trigger()

Question

I have a line of code as follows:

$('#type').val(target).trigger('change');

It opens a new div(it was display none). I want to run a code after that div opens and locates at DOM. How ca I do that?

I'm guessing from your question that the div is shown in response to the change event. If the div was display: none and all you're doing is showing it, it's already in the DOM tree. It should appear near instantaneously, no need to wait. If my guess is incorrect, the question needs (much) more information. — T.J. Crowder
– T.J. Crowder, Commented Nov 29, 2011 at 13:34

nicosantangelo · Accepted Answer · 2011-11-29 13:39:10Z

2

You could pass a function to the event and execute it like so:

$('#type').val(target).trigger('change', function() {
//do something
});

//in your event
$('#type').change(function(event, func) {
       //do things
       if(func) {
          func();
       }
});

answered Nov 29, 2011 at 13:39

nicosantangelo

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Comments

Keith.Abramo · Accepted Answer · 2011-11-29 13:56:11Z

0

You can create an event listener on that trigger just like you would any other native jQuery event.

//You can trigger it like you usually do or optionally pass in extra parameters in case you want your subscribed listeners to have access to that info
$('#type').val(target).trigger('change', param1, param2);

$('#type').live("change", function(event, param1, param2) {
       $("#myDiv").show();
});

answered Nov 29, 2011 at 13:56

Keith.Abramo

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