In my android application. I got binary code from a jpeg image from the code as follows.
byte[] val = stream.toByteArray();
BigInteger bi = new BigInteger(val);
String s = bi.toString(2);
This string s prints the binary value of the image. My question is how to convert this binary format into a jpeg image??
I'm not really sure what you want.
If you want to create a Bitmap-instance directly from the stream you can use BitmapFactory and display that Bitmap in an ImageView-instance afterwards:
Bitmap image = BitmapFactory.decodeStream(stream);
imageView.setImageBitmap(image);
If you want to convert your string representation with radix 2 back to a binary array you can use BigInteger too:
BigInteger bigInt = new BigInteger(s, 2);
byte[] binaryData = bigInt.toByteArray();
Bitmap bmp=BitmapFactory.decodeByteArray(val, 0, val.length);
ImageView img = new ImageView(this);
img.setImageBitmap(bmp);
Hope this Helps
Edit: To write in Internal Memory
FileOutputStream fout;
fout = openFileOutput("temp.jpg",Context.MODE_WORLD_WRITEABLE);
b1.compress(CompressFormat.JPEG, 100, fout);
To write in External Memory
FileOutputStream out = new FileOutputStream(Environment.getExternalStorageDirectory().getAbsolutePath()+"/temp.JPEG");
bm.compress(Bitmap.CompressFormat.JPEG,90, fout);
Bitmap bMap = BitmapFactory.decodeByteArray(bMapArray, 0, bMapArray.length);
savefile(bMap,"test.jpg");
private void savefile(Bitmap bt,String file)
{
try {
ContextWrapper context=this;
FileOutputStream stream =context.openFileOutput(file, 2);
BufferedOutputStream objectOut = null;
// FileOutputStream stream =(FileOutputStream) getAssets().open("temp.txt");
try {
objectOut = new BufferedOutputStream(stream);
bt.compress(Bitmap.CompressFormat.PNG, 100, objectOut);
objectOut.flush();
objectOut.close();
}
catch (Exception e) {
// TODO Auto-generated catch block
}
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
}
}
I've used this code in the past:
InputStream is = (InputStream)imageContent;
d = Drawable.createFromStream(is, "src");
