Getting function containing a line in Python

There is no built-in way to do this in python. However, you could define a function to do something like that, but it would handle modules as files in your current directory:

import re

def get_function_name(module, line):
    module_file = module.replace('.', '/') + '.py'
    lines = open(module_file, 'r').xreadlines()
    i = line - 1
    try:
        while i:
            tmp = next(lines)
            i -= 1
    except StopIteration:
        raise EOFError('Not enought lines in module %s' % module)
    function_line = next(lines)
    function_name =  re.match('def (\w+)\([^)]*\):', function_line)
    if function_name:
        return function_name.group(1)
    raise ValueError('No function declared on line %s' % line)

This function is opening the module passed as a file, iterating until reached the passed line, and then, searching the name of the function using regular expressions. If there was no function declared on the passed line or the line passed exceeded the number of lines of the file, it will raise an Error. E.g.:

>>> get_function_name('my_module.my_submodule', 24)
'my_function_name'
>>> get_function_name('my_module.my_submodule', 25)
    Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 15, in get_function_name
ValueError: No function declared on line 17
>>> get_function_name('my_module.my_submodule', 123456)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 10, in get_function_name
EOFError: Not enought lines in module