Getting substring based on particular index in xsl/xslt

Question

I have a long web url in my xsl variable. eg. @url = "http://stackoverflow.com/questions/ask/2434/35454"

I need a substring from this based on 3rd index of "/". i.e I want to display only http://stackoverflow.com

There is a substring(string, start, length) function in xsl but how do i find the length portion. I could not find any indexof function.

<xsl:value-of select="substring(url,1,length)"/>

My url is suppose - "http://stackoverflow.com/questions/ask/2434/35454" Output I want is http://stackoverflow.com

Please suggest some solutions.

Dimitre Novatchev · Accepted Answer · 2012-01-13 05:28:38Z

1

Use:

   concat(substring-before(.,'//'),
          '//',
          substring-before(substring-after(., '//'),
                           '/'
                           )
         )

Complete code example:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="/*">
  <xsl:value-of select=
  "concat(substring-before(.,'//'),
          '//',
          substring-before(substring-after(., '//'),
                           '/'
                           )
         )
  "/>
 </xsl:template>
</xsl:stylesheet>

when this transformation is applied on this XML document:

<t>http://stackoverflow.com/questions/ask/2434/35454</t>

the wanted, correct result is produced:

http://stackoverflow.com

answered Jan 13, 2012 at 5:28

Dimitre Novatchev

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2 Comments

AbhiRoczz... Over a year ago

So if my url is stored in $url I have to use like this. concat(substring-before(url,'//'), '//', substring-before(substring-after(url, '//'), '/' )

Dimitre Novatchev Over a year ago

@AbhiRoczz... Yes, but don't forget the $ character before the name of the variable.

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