GSON deserialize as array although JSON source is object

Question

I'd like to deserialize this using GSON into a list of Post, but can't figure out how to tell GSON how to ignore the root element "posts" (as its an object) and just process the array.

I've got:

Type postTypeList = new TypeToken<List<Post>>(){}.getType();

JsonParser jsonParser = new JsonParser();
JsonElement jsonElement = jsonParser.parse(myJSONString);
JsonObject postsRootObj = jsonElement.getAsJsonObject();

List<Post> postList = gson.fromJson(postsRootObj.get("posts"), postTypeList);

BUT.. I'd rather not have the whole JsonParser, I'd rather just pass it directly into the gson.fromJson function.. Is there a way to do this?

{ "posts":
  [      

        {
       "username": "John",  
       "message": "I'm back",
       "time": "2010-5-6 7:00:34"
        "validator":[{
                        "prog": "Name1",
                        "name": "Name2",
                        "computername": "Name3",
                        "date": "2010-11-20 19:39:55"
                      }]
        }
      ,

        {
          "username": "Smith",
          "message": "I've been waiting",
          "time": "2010-4-6 10:30:26"
           "validator":[{
                        "prog": "Name1",
                        "name": "Name2",
                        "computername": "Name3",
                        "date": "2010-11-20 19:39:55"
                      }]

       }
]}

Niks · Accepted Answer · 2012-02-01 10:08:00Z

1

Create a wrapper class which will have List<Post> as its member

public class PostList{
private List<Post> posts;
// getter and setters for posts
}

And then use fromJson in the similar fashion

List<Post> postList = gson.fromJson(myJSONString,PostList.class);

answered Feb 1, 2012 at 10:08

Niks

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2 Comments

monkey-wrench Over a year ago

This is the other approach I thought of, however in my opinion its an unnecessary class, I was just hoping something might have been built into GSON to assist with my problem.

Niks Over a year ago

Ohh okay! Hmmm..I could only think of this and the approach you wrote..Correct me if I'm wrong,but I don't think there will be any way to force Gson to completely ignore the root element..

vinzzz · Accepted Answer · 2016-11-30 18:49:57Z

0

There is a correction from above. Usage should be :

 PostList postList = gson.fromJson(myJSONString,PostList.class);
 Post post = postlist.get(index) //index is the index of list you want to access

answered Nov 30, 2016 at 18:49

vinzzz

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