Unix print loop outputs on one line

Question

I created this script and I want to print the outputs on one line, how do I do this? This is my script

#!/bin/bash

echo "enter start and stop numbers"

read start stop

while [ $start -lt $stop ]

do

echo $start

start=`expr $start + 1`

done

jaypal singh · Accepted Answer · 2012-01-20 08:34:29Z

4

Using printf or echo -n. Also, try to use start=$(($start + 1)) or start=$[$start + 1] instead of back ticks to increment the variable.

#!/bin/bash

echo "enter start and stop numbers"
read start stop
while [ $start -lt $stop ]
do
    printf "%d " $start
    start=$(($start + 1))
done

#!/bin/bash

echo "enter start and stop numbers"
read start stop
while [ $start -lt $stop ]
do
    echo -n "$start "  # Space will ensure output has one space between them
    start=$[$start + 1]
done

edited Jan 20, 2012 at 8:34

answered Jan 20, 2012 at 8:26

jaypal singh

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Comments

John Eipe · Accepted Answer · 2012-01-20 08:21:30Z

3

Use

echo -n $start

Check out: http://ss64.com/bash/echo.html

answered Jan 20, 2012 at 8:21

John Eipe

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Comments

raghvendra gupta · Accepted Answer · 2020-05-26 19:38:54Z

0

for ((i=1;i<=10;i++)); do echo -n $i; done; echo -e "\n"

edited May 26, 2020 at 19:38

answered May 26, 2020 at 19:32

raghvendra gupta

11 bronze badge

2 Comments

Michelle Over a year ago

Can you explain what your code does, and how it improves on the code in the question.

Lukasz Szczygielek Over a year ago

I agree with @Michelle - please also format your answer and use code formatting.

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