CodeIgniter; $this usage in non object context

Question

I am trying to edit my config/database.php within my CodeIgniter project so that I don't have to keep changing the database information every time I push a new version to the server. To do the latter, I have created a $debug variable, shown below, which checks against the uri to see if the site is being run on my localhost machine (where I build the project before upload) or on the actual server.

Unfortunately in the database.php file, I don't have access to the $this variable, and as I am personally new to OOP in PHP, I am not entirely sure of a way around this. Please can you tell me how I can do so?

Thanks,

Max.

Fatal error: Using $this when not in object context in application/config/database.php on line 51

$debug = strpos($this->uri->config->item('base_url'), 'localhost'); //line 51

$db['default']['hostname'] = $debug == TRUE ? 'x' : 'y';
$db['default']['username'] = $debug == TRUE ? 'x' : 'y';
$db['default']['password'] = $debug == TRUE ? 'x' : 'y';
$db['default']['database'] = $debug == TRUE ? 'x' : 'y';

I don't know CI, but I'm pretty sure that there's a better way to define alternate database configurations. I think that should be your actual question. — deceze
– deceze ♦, Commented Feb 17, 2012 at 1:32
possible duplicate of Call to a member function on a non-object — tereško
– tereško, Commented Feb 17, 2013 at 11:31
@deceze I just saw your comment, can you give an example, and what's wrong with the current method? — max_
– max_, Commented Feb 21, 2013 at 23:33

Sam Dufel · Accepted Answer · 2012-02-17 01:34:07Z

13

You need to a get an instance of the codeigniter object -

$CI = get_instance();

For older versions of php, use =&

Then, use $CI wherever you would normally use $this

answered Feb 17, 2012 at 1:34

Sam Dufel

17.6k3 gold badges51 silver badges52 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Joe · Accepted Answer · 2012-02-17 01:35:16Z

2

You need to use get_instance() to get the $this variable.

$ci = get_instance(); // $ci replaces $this
echo $ci->config->item('base_url');

The $this variable is a special variable used in object oriented code, when you have classes - see php.net for some background reading on it.

answered Feb 17, 2012 at 1:35

Joe

15.8k4 gold badges52 silver badges84 bronze badges

Comments

Pulkit Goyal · Accepted Answer · 2012-02-17 16:26:35Z

0

$this is only for objects, you cannot use it outside an object. Best way to do this, I believe, is to exclude database.php file when you deploy. The IDE you use should have an option to exclude file from deployment.

edited Feb 17, 2012 at 16:26

Pulkit Goyal

5,6821 gold badge34 silver badges50 bronze badges

answered Feb 17, 2012 at 1:38

gehad

1,3553 gold badges12 silver badges17 bronze badges

Comments

PK. · Accepted Answer · 2012-02-18 12:48:31Z

0

There's a simple answer to this problem.

Read Environment section at: http://codeigniter.com/user_guide/libraries/config.html

basically create two folders application/config/production and application/config/development

and put one copy of your database.php in each folder.

answered Feb 18, 2012 at 12:48

PK.

2,6313 gold badges25 silver badges31 bronze badges

Comments

Timo · Accepted Answer · 2013-05-03 19:31:41Z

0

You can also use $_SERVER['SERVER_NAME'] and compare it with your server names (localhost or remote). There is a function in CI that checks for it:

$this->input-> server('SERVER_NAME')

As written above, you have to change the this if not in object context.

answered May 3, 2013 at 19:31

Timo

3,2533 gold badges36 silver badges34 bronze badges

Collectives™ on Stack Overflow

CodeIgniter; $this usage in non object context

5 Answers 5

Comments

Comments

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

5 Answers 5

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related