Fast component labelling in python and opencv

Question

I'm implementing the component labelling algorithm as in this paper using python and opencv. It requires checking the input image pixel-by-pixel and perform the so-called contour tracing subroutine to assign label to the blobs of a binary image.

I manage to have it running, but it seems very slow. Profiling the code shows that the for-loop to access the pixels seems to be the bottleneck. It takes about 200ms for a 256px*256px image. Here's roughly what I do:

for i in image.height:
    for j in image.width:
        p = image[i, j]
            pa = image[i - 1, j]
            pb = image[i + 1, j] 
            # etc...

where "image" is a binary opencv image.

I wonder if there's a faster way of doing it so that it's usable also for video applications. I'm targeting something like 40-50ms running time for the same problem size, to get 20-25fps. 10-15fps would probably be acceptable as well (66-100ms running time).

Any hints, ideas what I can do is much appreciated.

Python isn't exactly a high performance language here... Try again with Java, C/C++, or something faster. — Samuel Audet
– Samuel Audet, Commented Feb 19, 2012 at 5:42

malloc47 · Accepted Answer · 2012-02-19 02:52:47Z

1

The latest OpenCV bindings for Python return numpy data types, meaning you have the full numpy arsenal at your disposal. Looping over a 2D array in numpy (with indices) is generally done with an ndenumerate, which should offer at least a little speedup (since it's a single loop optimized for N-D arrays). You could look into numpy vectorize which would yield even more speedup, but if you need the indices of the array, then an ndenumerate would be what you need.

Beyond this, your best bet may be writing bottleneck operations in C.

Update

If it would help, I believe scipy.ndimage.label does exactly what you're attempting to do, and might even use the same algorithm.

edited Feb 19, 2012 at 2:52

answered Feb 18, 2012 at 22:20

malloc47

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Comments

wil · Accepted Answer · 2013-02-18 20:16:19Z

Many are the posts I've seen lamenting the lack of OpenCV labeling.

As @malloc47 said, scipy.ndimage.label will work. I've used it, but I wasn't happy with its performance while I was looking for the largest blob in an image. I didn't specifically need a labeling, so I ended up using the cv2.findContours and cv2.contourArea to isolate the largest one:

# The [0] is because I didn't care about the hierarchy, which is the second
# return value of cv2.findContours.
contours = cv2.findContours(numpy_array,
                            mode=cv2.RETR_EXTERNAL,
                            method=cv2.CHAIN_APPROX_SIMPLE
                            )[0]

areas = [cv2.contourArea(ctr) for ctr in contours]
max_contour = [contours[areas.index(max(areas))]]

This ended up being a lot faster for me than scipy.ndimage.label for very similar results. As I said, this isn't exactly a labeling, but one could probably use the contour finder to give a reasonably good labeling.

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