Yii dynamic dropdown output to view

Question

Using this wiki I have a dynamic dropdownlist working just fine. Instead of the related data populating another dropdownlist I just want all the related values to display at once on the screen in some sort of formatted list.

I changed the update in the ajax action to 'update'=>'#cities', and added to my view...

<div id="cities"> 
   <?php echo $model->relatedCities; ?>
</div

and to my model

public function getRelatedCities()
{
   $out=CHtml::listData($this->cities,'CityId','Name');
   return implode('<br />', $out);
}

When I make my selection in my dropdownlist nothing is updated in <div id="cities"> and the ajax call in firebug looks fine.

So how can I display the dynamic related content from the dropdownlist all at once?

Might be wrong, but shouldn't $model->relatedCities be $model->RelatedCities? — Avanche
– Avanche, Commented Feb 24, 2012 at 0:11
Have you confirmed that $out is actually returning something? — Avanche
– Avanche, Commented Feb 24, 2012 at 0:38

bool.dev · Accepted Answer · 2012-02-24 03:22:57Z

2

This is a problem with your action, you have to echo instead of return.

Because your ajax call is expecting html data, and not some string.
So try this:

public function getRelatedCities()
{
 $out=CHtml::listData($this->cities,'CityId','Name');
 echo implode('<br />', $out);
}

p.s: Assuming that you have verified that $out is not empty.

answered Feb 24, 2012 at 3:22

bool.dev

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bool.dev Over a year ago

ask for clarifications if needed.

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