Programmatically stop execution of python script after running condition statement

Question

How do you programmatically stop a python script after a condition sentence has run through. In the pseudo script below:

for row in rows:

    if row.FIRSTDATE == row.SECONDDATE:
        pass
    else:
        print "FIRSTDATE does not match SECONDDATE " + row.UNIQUEID

## If I set my quit sequence at the this tab level, it quits after the first
## unmatched record is found. I don't want that, I want it to quit after all the
## unmatched records have been found, if any. if all records match, I want the
## script to continue and not quit

        sys.quit("Ending Script")

Thanks, Mike

Irfy · Accepted Answer · 2012-03-05 23:54:44Z

2

quit_flag = False
for row in rows:

    if row.FIRSTDATE == row.SECONDDATE:
        pass
    else:
        print "FIRSTDATE does not match SECONDDATE " + row.UNIQUEID
        quit_flag = True

if quit_flag:
    print "Ending Script"
    sys.exit()

answered Mar 5, 2012 at 23:54

Irfy

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Comments

Joran Beasley · Accepted Answer · 2012-03-05 23:58:10Z

1

not sure if i understand correctly

doQuit = 0
for row in rows:
    if row.FIRSTDATE != row.SECONDDATE:
        print "FIRSTDATE does not match SECONDDATE " + row.UNIQUEID
        doQuit = 1
if doQuit: sys.exit()

answered Mar 5, 2012 at 23:58

Joran Beasley

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1 Comment

Mike Over a year ago

Thanks Joran. This does exactly what I wanted.

campos.ddc · Accepted Answer · 2012-03-06 20:59:53Z

1

I would do it like this:

def DifferentDates(row):
    if row.FIRSTDATE != row.SECONDDATE:
        print "FIRSTDATE does not match SECONDDATE " + row.UNIQUEID
        return True
    else:
        return False

# Fill a list with Trues and Falses, using the check above
checked_rows = map(DifferentDates, rows)

# If any one row is different, sys exit
if any(checked_rows):
    sys.exit()

Documentation for any

edited Mar 6, 2012 at 20:59

answered Mar 6, 2012 at 0:35

campos.ddc

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2 Comments

Mike Over a year ago

Thanks Campos. I tried using this and it's exiting for me. I was playing around with your suggestion to add print lines to the function. I placed them at the same tab level as 'return' but that doesn't seem to print for me. How would I set a print line to return any unmatched records? Thanks!

campos.ddc Over a year ago

@mike-macrae Edited to add prints; That 'else' is not necessary, but it's there for clarity.

Burhan Khalid · Accepted Answer · 2012-10-04 11:29:09Z

1

Another approach:

mis_match = []

for row in rows:
    if row.FIRSTDATE != row.SECONDDATE:
        mis_match.append(row.UNIQUEID)

if mis_match:
  print "The following rows didn't match" + '\n'.join(mis_match)
  sys.exit()

answered Oct 4, 2012 at 11:29

Burhan Khalid

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