xcode filter NSMutableArray elements by string contents

Question

I would like to filter NSMutableArray elements that contains "some" string. ListArchives is filled with string elements and listFiles must be a filtered one. XCode generates an alert at last posted line. What am doing wrong? any other method to filter elements of NSMutableArray?

NSString *match = @"*some*"; 
listFiles = [[NSMutableArray alloc] init];

NSPredicate *sPredicate = [NSPredicate predicateWithFormat:@"SELF like[cd] %@", match];

listFiles = [listArchives filteredArrayUsingPredicate:sPredicate];

Sergey Kalinichenko · Accepted Answer · 2014-07-14 09:21:32Z

4

Try using contains instead of like, for example as follows:

NSString *match = @"some"; 
listFiles = [[NSMutableArray alloc] init];

NSPredicate *sPredicate = [NSPredicate predicateWithFormat:@"SELF CONTAINS[cd] %@", match];

listFiles = [[listArchives filteredArrayUsingPredicate:sPredicate] mutableCopy];

edited Jul 14, 2014 at 9:21

answered Apr 2, 2012 at 17:08

Sergey Kalinichenko

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4 Comments

Jaume Over a year ago

ok, seems better option. However still showing an alert, "Incomptaible pointer types assigning to NSMutableArray _strong from NSArray". So if I declare listFiles as NSArray solves it but no other way to get listFiles also mutable?

Sergey Kalinichenko Over a year ago

@Jaume This is because the filtered array is not known to the compiler to be an NSMutableArray. Try this instead of the last line: [listFiles setArray:[listArchives filteredArrayUsingPredicate:sPredicate]];

Nazir Over a year ago

last line listFiles = [[listArchives filteredArrayUsingPredicate:sPredicate] mutableCopy]

Sergey Kalinichenko Over a year ago

@Nazir Thanks! You can always suggest an edit - it's often faster than writing a comment.

YvesLeBorg · Accepted Answer · 2016-08-06 14:44:03Z

2

If you want to search as 'like' operator. Lets say you have a NSArray with following contents :

static int count = 0;
NSArray *results = [NSArray arrayWithObjects:@"What was", @"What is", @"What will", nil];

NSString *targetString = @"What"
for (NSString *strObj in results)
{
    if ([strObj rangeOfString:targetString].location != NSNotFound){
        NSLog (@"Found: %@", strObj);
        count = count + 1;              
    }
}
NSLog(@"There were %d occurence of %@ string",count,targetString);

edited Aug 6, 2016 at 14:44

YvesLeBorg

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answered Apr 2, 2012 at 17:19

Praveen-K

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Comments

Hemang · Accepted Answer · 2012-10-11 07:39:49Z

0

NSString *match = @"some";
listFiles = [[NSMutableArray alloc] init];
NSPredicate *sPredicate = [NSPredicate predicateWithFormat:@"SELF BEGINSWITH[c] %@", match];
listFiles = [listArchives filteredArrayUsingPredicate:sPredicate];

For robust searching this can serve you as some what "Like" serve in SQL.

edited Oct 11, 2012 at 7:39

Hemang

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answered Oct 11, 2012 at 7:35

umer sufyan

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