Android custom XML parser fails to resolve android namespace

Question

I would like to get the correct way of parsing custom android tags with an XmlResourceParser. I am using Eclipse 3.6 with the android plug-in, and I would like some attributes like the name be expanded with the full string from strings.xml.

Here is the index.xml which is being parsed in the res/xml/ folder.

<?xml version="1.0" encoding="utf-8"?>
<Index xmlns:android="http://schemas.android.com/apk/res/android">
<Sheet
    shortName="o_2sq"
    android:name="@string/o_2sq"
    instructions=""
/>
</Index>

Here is the file strings.xml in the res/values/ folder

<?xml version="1.0" encoding="utf-8"?>
<resources>
<string name="o_2sq">Organize two squares</string>
</resources>

and the code fragment that parses the first index.xml with an XmlResourceParser:

String name = xpp.getAttributeValue(null, "android:name");
String shortName = xpp.getAttributeValue(null, "shortName");

The variable name contains null, but shortName contains "o_2sq". I also tried the following without success:

String name = xpp.getAttributeValue("android", "name");

What is the correct way of writing the sentence so that the variable name would contain "Organize two squares" ?

skywall · Accepted Answer · 2012-04-12 12:29:51Z

5

Try this:

String name = xpp.getAttributeValue("http://schemas.android.com/apk/res/android", "name");

edited Apr 12, 2012 at 12:29

answered Apr 12, 2012 at 12:21

skywall

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2 Comments

Mikaël Mayer Over a year ago

Nice try. It gives something better : my variable name now contains the string "@2131099651". Not sure why.

skywall Over a year ago

It is probably string resource ID. Try to use getString( number ); method to get string.

androidyue · Accepted Answer · 2014-07-30 11:55:54Z

2

final String NAMESPACE_ANDROID = "http://schemas.android.com/apk/res/android";
final int VALUE_NOT_SET = -1;
int resId = parser.getAttributeResourceValue(NAMESPACE_ANDROID, "name", VALUE_NOT_SET);
String value = null;
if (VALUE_NOT_SET != resId) {
    value = context.getString(resId);
}

I think the above code could help you.

answered Jul 30, 2014 at 11:55

androidyue

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Comments

Mikaël Mayer · Accepted Answer · 2012-05-11 06:49:07Z

1

Best solution I found to overcome that problem.

String s = xpp.getAttributeValue("http://schemas.android.com/apk/res/android", "name");
String name = null;
if(s != null && s.length() > 1 && s.charAt(0) == '@') {
  int id = Integer.parseInt(s.substring(1));
  name = getString(id);
} else {
  name = "";
}

answered May 11, 2012 at 6:49

Mikaël Mayer

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2 Comments

William T. Mallard Over a year ago

Did you mean else { name = s' } ? Seems like that would allow that attribute to be either a resource or a hard-coded string, no?

Mikaël Mayer Over a year ago

I needed name to be not null in my case. This is why.

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