What's the easiest way in python to concatenate string with binary values ?
sep = 0x1
data = ["abc","def","ghi","jkl"]
Looking for result data "abc0x1def0x1ghi0x1jkl" with the 0x1 being binary value not string "0x1".
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No binary values there. 0x1 is hexadecimal; 0b1 would be binary.foobarbecue– foobarbecue2017-11-02 02:37:01 +00:00Commented Nov 2, 2017 at 2:37
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3 Answers
I think
joined = '\x01'.join(data)
should do it. \x01 is the escape sequence for a byte with value 0x01.
3 Comments
stefanB
+1 Great thanks, I tried similar thing but did not think about escaping the characters to create a 'character' ...
stefanB
Works great: 8=10^A9=ABC^A10=BBB^A34=D
user2284570
@pdc : This doesn’t work with mmap.
The chr() function will have the effect of translating a variable into a string with the binary value you are looking for.
>>> sep = 0x1
>>> sepc = chr(sep)
>>> sepc
'\x01'
The join() function can then be used to concat a series of strings with your binary value as a separator.
>>> data = ['abc']*3
>>> data
['abc', 'abc', 'abc']
>>> sepc.join(data)
'abc\x01abc\x01abc'
1 Comment
user2284570
@ricree : This doesn’t work with mmap.
I know this isn't the best method, but another way that could be useful in different context for the same question is:
>>> x=(str(bin(0b110011000)))
>>> b=(str(bin(0b11111111111)))
>>> print(x+b)
0b1100110000b11111111111
And if needed, to remove the left-most two bits of each string (i.e. 0b pad) the slice function [2:] with a value of 2 works:
>>> x=(str(bin(0b110011000)[2:]))
>>> b=(str(bin(0b11111111111)[2:]))
>>> print(x+b)
11001100011111111111
