I want to create a directory structure like this in nix:
mkdir -p 1,2,3,4,5,6,7,8,9 and within each of these folders I want folders 1,2,3,4,5,6,7,8,9
I have started to write a simple loop like this (all the way up to folder 2) but this seems inefficient.
#!/usr/bin/env bash
for i in 1 2 4 5 6 7 8 9; do mkdir -p 1/{1,2,3,4,5,6,7,8,9} $i, mkdir -p 2/{1,2,3,4,5,6,7,8,9} $2; done
Is there a better way of doing it?
This should help (requires bash):
mkdir -p {1,2,3,4,5,6,7,8,9}/{1,2,3,4,5,6,7,8,9}
Some newer versions of bash also allow this:
mkdir -p {1..9}/{1..9}
Sounds simple enough unless I've misunderstood:
#!/bin/sh
for i in `seq 1 9`; do
for j in `seq 1 9`; do
mkdir -p $i/$j
done
done
Perl Solution.
for($counter = 1; $counter <= 9; $counter++)
{
`mkdir -p $counter/{1..9}`; //Executing Unix Command
}
