JavaScript - Split A String

Question

I have a variable that holds the value 'website.html'.

How can I split that variable so it only gives me the 'website'?

Thanks

@Jack This page was the first hit when I Googled "javascript split string dot". Saying "Google it" helps no one. — Emile Cormier
– Emile Cormier, Commented Jan 27, 2018 at 4:24

paulslater19 · Accepted Answer · 2018-04-18 09:37:31Z

42

var a = "website.html";
var name = a.split(".")[0];

If the file name has a dot in the name, you could try...

var a = "website.old.html";
var nameSplit = a.split(".");
nameSplit.pop();    
var name = nameSplit.join(".");

But if the file name is something like my.old.file.tar.gz, then it will think my.old.file.tar is the file name

edited Apr 18, 2018 at 9:37

answered May 5, 2012 at 18:12

paulslater19

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2 Comments

Anton Over a year ago

This does not work, if the filename has a dot in its name like: my.super.website.html.

Owais Over a year ago

var nameSplit = a.split("."); nameSplit.pop(); var name = nameSplit.join("."); Make nameSplit.join(".") instead of name.join(".") , It will work.

K2xL · Accepted Answer · 2012-05-05 18:13:23Z

4

String[] splitString = "website.html".split(".");
String prefix = splitString[0];

*Edit, I could've sworn you put Java not javascript

var splitString = "website.html".split(".");
var prefix = splitString[0];

answered May 5, 2012 at 18:13

K2xL

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Comments

JonnyReeves · Accepted Answer · 2012-05-05 18:17:33Z

3

Another way of doing things using some String manipulation.

var myString = "website.html";
var dotPosition = myString.indexOf(".");
var theBitBeforeTheDot = myString.substring(0, dotPosition);

answered May 5, 2012 at 18:17

JonnyReeves

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4 Comments

Ricardo Souza Over a year ago

+1 This requires more code, but don't requires aditional comments to understand.

JonnyReeves Over a year ago

I remember learning basic string manipulation before the quicker 'Array.split' method clicked with me (:

paulslater19 Over a year ago

It's worth noting that some older browsers do not support .indexOf()

paulslater19 Over a year ago

@JonnyReeves Whoops, yes, you're right - I was thinking about [].indexOf

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