PHP associative array index undefined

Question

Without looping a set of array keys acquired via array_keys($array), how else can I select the key of an array such that $array["key"] where "key" associates to a second subsequent array -- PHP otherwise outputs a notice stating that "key" is undefined.

Any help is sincerely appreciated.

Post some code, or at least a plain-text array structure. It's difficult to tell what you're asking. — user895378
– user895378, Commented May 25, 2012 at 3:25
Apologies. The problem I have is testing if the declaration is false, such that e.g. if(!($array["index"] = $value)) { //output error } or by if($array["index"] != $value) { //output error } — user784446
– user784446, Commented May 25, 2012 at 3:31

Niet the Dark Absol · Accepted Answer · 2012-05-25 02:52:21Z

2

I think you're looking for isset(), for example if( isset($array['key'])) ...

answered May 25, 2012 at 2:52

Niet the Dark Absol

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7 Comments

user784446 Over a year ago

The key is already set though (e.g. array_push($array["key"], $value) should return true)

user784446 Over a year ago

Thanks, but it still doesn't solve the problem -- PHP is still outputting an undefined response.

user784446 Over a year ago

Hmm, suppose I append an associative value by the following means: if($array["index"] != $value) { print "Cannot append value"; } Will that force the value to be false?

Blair McMillan Over a year ago

That doesn't append anything, it's just testing the value of it.

user784446 Over a year ago

I want to test if the assignment is true, i.e. if it succeeded.

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JeffK · Accepted Answer · 2013-12-02 20:40:10Z

0

isset() works for variables, but the error your likely getting is for an undefined key/index. You'll want to try array_key_exists() before trying to use the key (and based on the results, either use or create the key).

http://www.php.net/manual/en/function.array-key-exists.php

answered Dec 2, 2013 at 20:40

JeffK

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