Passing js variable into php string

Question

I need a little bit of help im trying to page a js variable into a url thats being parsed in php using file_get_contents. Im not sure where to start to do that.

<script type="text/javascript">
var js_variable = appl+goog+fb+mfst+nflx;
</script>

<?php
$ticker = js_varable_here;
$file = file_get_contents('http://finance.yahoo.com/d/quotes.csv?s=$ticker&f=soac1p2ghjkj1re');

?>

any advice is appreciated, like i said im in the dark on this one.

php runs on server and js resides at client. First it gets to server and than to client. You cant pass like that. You can use ajax though — Jashwant
– Jashwant, Commented May 25, 2012 at 21:58
is the js_variable set in your source code (which is what is in your example) or is it set on the client side (a more likely use case)? — Aerik
– Aerik, Commented May 25, 2012 at 22:11

user1418338 · Accepted Answer · 2012-05-25 22:11:05Z

2

Here's an example using jquery.

Javascript:

<script type="text/javascript">
  var js_variable = appl+goog+fb+mfst+nflx;
  $.post("/somephp.php", {ticker: js_variable}, function(data) {
    // returned from php
  });
</script>

PHP:

 <?php
   $ticker = $_POST['ticker'];
   $file = file_get_contents("http://finance.yahoo.com/d/quotes.csv?s=$ticker&f=soac1p2ghjkj1re");
 ?>

answered May 25, 2012 at 22:11

user1418338

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2 Comments

Suzed Over a year ago

so the php part would go into the somephp.php file? just so i understand correctly

user1418338 Over a year ago

@Suzed yes. In this example, that's where the PHP would go. You can also change the url in the javascript to "./" if you are mixing html and php. (Which means you should probably add some logic in the PHP portion so that it detects a post request.)

nwpan · Accepted Answer · 2012-05-25 22:08:33Z

1

Expanding on what Jashwant says...

PHP is a server-sided language, which does work behind the scenes. Javascript is client-side, which runs and executes code on the local client's machine (ie through the browser).

You can however use AJAX (Asynchronous JavaScript and XML) so the local client sends HTTP requests to the server without reloading the current page. For instance, you can use AJAX to send the contents of the variable to the server.

For easier usage, you should check out jQuery's methods regarding ajax calls. See: http://api.jquery.com/jQuery.ajax/

Hope it works well.

answered May 25, 2012 at 22:08

nwpan

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Comments

Lawrence Cherone · Accepted Answer · 2012-05-25 22:41:21Z

1

Heres how you can do it with jquerys post() and then return json, you could build the result as you expect to output within the php part or you could use jquery to loop with each() through the result.

<?php
if($_SERVER['REQUEST_METHOD']=='POST'
   && isset($_SERVER['HTTP_X_REQUESTED_WITH'])
   && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) === 'xmlhttprequest'){

    if(!empty($_POST['s'])){

        $ticker = $_POST['s'];
        $file = file_get_contents('http://finance.yahoo.com/d/quotes.csv?s='.$ticker.'&f=soac1p2ghjkj1re');

        header('Content-Type: application/json');
        echo json_encode(array('result'=>$file));
    }else{
        echo 'Request not allowed!';
    }
    die;
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" 
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js" charset="utf-8"></script>
<script>
var js_variable = "appl+goog+fb+mfst+nflx";

$.post('this_script.php',{s: js_variable}, function(data) {
  $('#divResult').replaceWith('<div id="divResult">'+ data.result +'<div>');
});
</script>
</head>
<body>

<div id="divResult"><div>
</body>
</html>

answered May 25, 2012 at 22:41

Lawrence Cherone

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4 Comments

Suzed Over a year ago

i tested your code just to see if there was much of a difference and it doesnt seem to work, data comes back as undefined

Lawrence Cherone Over a year ago

Its working for me, have you changed this_script.php in the jquery post?

Lawrence Cherone Over a year ago

also you should see if $file contains anything. perhaps FGC is not enabled.

Suzed Over a year ago

I changed this_script to / so it is working from the same file and if you change the js_variable it to goog, it should return values. but other then that nothing was changed

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