Just the regex. They both replace all :)

http://docs.oracle.com/javase/8/docs/api/java/lang/String.html

PS:

There's also a replaceFirst() (which takes a regex)

Both replace() and replaceAll() replace all occurrences in the String.

Examples

I always find examples helpful to understand the differences.

replace()

Use replace() if you just want to replace some char with another char or some String with another String (actually CharSequence).

Example 1

Replace all occurrences of the character x with o.

String myString = "__x___x___x_x____xx_";

char oldChar = 'x';
char newChar = 'o';

String newString = myString.replace(oldChar, newChar);
// __o___o___o_o____oo_

Example 2

Replace all occurrences of the string fish with sheep.

String myString = "one fish, two fish, three fish";

String target = "fish";
String replacement = "sheep";

String newString = myString.replace(target, replacement);
// one sheep, two sheep, three sheep

replaceAll()

Use replaceAll() if you want to use a regular expression pattern.

Example 3

Replace any number with an x.

String myString = "__1_6____3__6_345____0";

String regex = "\\d";
String replacement = "x";

String newString = myString.replaceAll(regex, replacement); 
// __x_x____x__x_xxx____x

Example 4

Remove all whitespace.

String myString = "   Horse         Cow\n\n   \r Camel \t\t Sheep \n Goat        ";

String regex = "\\s";
String replacement = "";

String newString = myString.replaceAll(regex, replacement); 
// HorseCowCamelSheepGoat

See also

Documentation

• replace(char oldChar, char newChar)
• replace(CharSequence target, CharSequence replacement)
• replaceAll(String regex, String replacement)
• replaceFirst(String regex, String replacement)

Regular Expressions

• Tutorial
• List of patterns

The replace() method is overloaded to accept both a primitive char and a CharSequence as arguments.

Now as far as the performance is concerned, the replace() method is a bit faster than replaceAll() because the latter first compiles the regex pattern and then matches before finally replacing whereas the former simply matches for the provided argument and replaces.

Since we know the regex pattern matching is a bit more complex and consequently slower, then preferring replace() over replaceAll() is suggested whenever possible.

For example, for simple substitutions like you mentioned, it is better to use:

replace('.', '\\');

instead of:

replaceAll("\\.", "\\\\");

Note: the above conversion method arguments are system-dependent.

1. Both replace() and replaceAll() accepts two arguments and replaces all occurrences of the first substring(first argument) in a string with the second substring (second argument).
2. replace() accepts a pair of char or charsequence and replaceAll() accepts a pair of regex.

3. It is not true that replace() works faster than replaceAll() since both uses the same code in its implementation

   Pattern.compile(regex).matcher(this).replaceAll(replacement);

Now the question is when to use replace and when to use replaceAll(). When you want to replace a substring with another substring regardless of its place of occurrence in the string use replace(). But if you have some particular preference or condition like replace only those substrings at the beginning or end of a string use replaceAll(). Here are some examples to prove my point:

String str = new String("==qwerty==").replaceAll("^==", "?"); \\str: "?qwerty=="
String str = new String("==qwerty==").replaceAll("==$", "?"); \\str: "==qwerty?"
String str = new String("===qwerty==").replaceAll("(=)+", "?"); \\str: "?qwerty?"

String replace(char oldChar, char newChar)

Returns a new string resulting from replacing all occurrences of oldChar in this string with newChar.

String replaceAll(String regex, String replacement

Replaces each substring of this string that matches the given regular expression with the given replacement.

To throw more light with an example into how both are going to work for below code:

public static void main(String[] args)
{
    String s = "My\\s aaab\\s is\\s aaab\\s name";
    String s1 = s.replace("\\s", "c");
    System.out.println(s1);
    String s2 = s.replaceAll("\\s", "c");
    System.out.println(s2);
}

Output:

Myc aaabc isc aaabc name
My\scaaab\scis\scaaab\scname

Explanation

s.replace replaces "\\s" sequence of characters with c. Hence, the output in first line. s.replaceAll considers \\s as a regex rather(equivalent to space) and replaces spaces with c. \\s in String s is escaped with first \ encountered and becomes \s.

Intellij Idea is smart enough to notify you of the usage as well. If you take a closer look at below image, you will see the difference in interpretation by Intellij idea for replace and replaceAll usage.

Old thread I know but I am sort of new to Java and discover one of it's strange things. I have used String.replaceAll() but get unpredictable results.

Something like this mess up the string:

sUrl = sUrl.replaceAll( "./", "//").replaceAll( "//", "/");

So I designed this function to get around the weird problem:

//String.replaceAll does not work OK, that's why this function is here
public String strReplace( String s1, String s2, String s ) 
{
    if((( s == null ) || (s.length() == 0 )) || (( s1 == null ) || (s1.length() == 0 )))
     { return s; }

   while( (s != null) && (s.indexOf( s1 ) >= 0) )
    { s = s.replace( s1, s2 ); }
  return s;
}

Which make you able to do:

sUrl=this.strReplace("./", "//", sUrl );
sUrl=this.strReplace( "//", "/", sUrl );

As alluded to in wickeD's answer, with replaceAll the replacement string is handled differently between replace and replaceAll. I expected a[3] and a[4] to have the same value, but they are different.

public static void main(String[] args) {
    String[] a = new String[5];
    a[0] = "\\";
    a[1] = "X";
    a[2] = a[0] + a[1];
    a[3] = a[1].replaceAll("X", a[0] + "X");
    a[4] = a[1].replace("X", a[0] + "X");

    for (String s : a) {
        System.out.println(s + "\t" + s.length());
    }
}

The output of this is:

\   1
X   1
\X  2
X   1
\X  2

This is different from perl where the replacement does not require the extra level of escaping:

#!/bin/perl
$esc = "\\";
$s = "X";

$s =~ s/X/${esc}X/;
print "$s " . length($s) . "\n";

which prints \X 2

This can be quite a nuisance, as when trying to use the value returned by java.sql.DatabaseMetaData.getSearchStringEscape() with replaceAll().

From Java 9 there is some optimizations in replace method.

In Java 8 it uses a regex.

public String replace(CharSequence target, CharSequence replacement) {
    return Pattern.compile(target.toString(), Pattern.LITERAL).matcher(
            this).replaceAll(Matcher.quoteReplacement(replacement.toString()));
}

From Java 9 and on.

And Stringlatin implementation.

Which perform way better.

https://medium.com/madhash/composite-pattern-in-a-nutshell-ad1bf78479cc?source=post_internal_links---------2------------------

replace() method doesn't uses regex pattern whereas replaceAll() method uses regex pattern. So replace() performs faster than replaceAll().

To add to the already selected "Best Answer" (and others that are just as good like Suragch's), String.replace() is constrained by replacing characters that are sequential (thus taking CharSequence). However, String.replaceAll() is not constrained by replacing sequential characters only. You could replace non-sequential characters as well as long as your regular expression is constructed in such a way.

Also (most importantly and painfully obvious), replace() can only replace literal values; whereas replaceAll can replace 'like' sequences (not necessarily identical).