php numeric array

Question

I am a PHP beginner and I want to do the following:

I want to compare an array of numbers to an itemid. Currently, my code only works if I state which position of the array to check (productId). How can I check productId to test the whole contents of the array?

$productId = array(146,147,148,149,150,151,152,153,154,155,158,159,160,161,162,
                   163,113,116,117,118,114,119,120,121,115,121,122,123,124);

if(($_REQUEST['view'] == 'article') && ( $_REQUEST['Itemid'] == $productId[0])) {
    $setCol = 1;
    $setId = "main-noleft"; 
} else {
    $setCol = null;
    $setId = "main";
}

Vladimir Kadalashvili · Accepted Answer · 2012-07-03 11:11:45Z

4

in_array($_REQUEST['Itemid'], $productId)

answered Jul 3, 2012 at 11:11

Vladimir Kadalashvili

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J. Bruni · Accepted Answer · 2012-07-03 11:11:37Z

1

Use the in_array function: http://php.net/in_array

answered Jul 3, 2012 at 11:11

J. Bruni

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Comments

Abhishek · Accepted Answer · 2012-07-03 11:18:33Z

0

you can also use this
array_search( $_REQUEST['Itemid'], $productId )

array_search Searches the array for a given value and returns the corresponding key if successful
array_search

answered Jul 3, 2012 at 11:18

Abhishek

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