Passing values between modules in Python

Question

I want to know how to pass values between modules in Python.

In generate_image.py I have:

def gerenate_image(fr,to,lat1,lon1,lat2,lon2):
    output_image_name = spatial_matrix.plot_spatial_data(data_array,data_array.shape[0],data_array.shape[1],float(lon1)/10000,float(lon2)/10000,float(lat1)/10000,float(lat2)/10000,fr,to)
return()

In overlay.py, I want to use the "output_image_name",so I tried:

import generate_image

def overlay():
    overlay = generate_image.output_image_name
    ....

but it didn't work. So how can I retrieve the value of output_image_name?Thanks.

This is one of those situations where I recommend you read the Python tutorial from cover to cover. — Martijn Pieters
– Martijn Pieters, Commented Jul 11, 2012 at 8:38

Jakob Bowyer · Accepted Answer · 2012-07-11 08:38:24Z

4

Make your function return something.

def generate_image(fr,to,lat1,lon1,lat2,lon2):
    return spatial_matrix.plot_spatial_data(data_array,data_array.shape[0],data_array.shape[1],float(lon1)/10000,float(lon2)/10000,float(lat1)/10000,float(lat2)/10000,fr,to)

Then in the other place import and call the function.

from yourmodule import generate_image

def overlay():
    background = generate_image(*args) # Or what ever arguments you want.

answered Jul 11, 2012 at 8:38

Jakob Bowyer

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1 Comment

oops Over a year ago

Thank you for your answer! but the problem now is that the args in generate_image involves a lots of other modules and I have to import them all..is there an easier way to pass the value of "output_image_name" in gerenate_image.py?

Otto Allmendinger · Accepted Answer · 2012-07-11 08:45:16Z

1

In overlay.py:

def gerenate_image(fr,to,lat1,lon1,lat2,lon2):
    return spatial_matrix.plot_spatial_data(...)

In generate_image.py:

import generate_image

def overlay():
    overlay = generate_image.generate_image(...)

edited Jul 11, 2012 at 8:45

answered Jul 11, 2012 at 8:39

Otto Allmendinger

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4 Comments

Jakob Bowyer Over a year ago

Yes that and on overlay = generate_image.generate_image() where it expects 6 arguments and you give it none.

Otto Allmendinger Over a year ago

That wouldn't be a syntax error. I've shortened the code to get the main point across.

Jakob Bowyer Over a year ago

But people that didn't know that would try to run it, get a syntax error

Otto Allmendinger Over a year ago

Calling a function with the wrong number of arguments is a TypeError

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