PHP Get minimum value of a key in array of arrays

Question

I have an array like this:

$array = array(
    array('id' => 1, 'quantity' => 10),
    array('id' => 2, 'quantity' => 25),
    array('id' => 3, 'quantity' => 38),
    ...
);

I want to find the array contains minimum of quantity. How can I do it simply in one two lines of code?! (I prefer to use PHP functions)

Also if the variable is an Object, Does it make any difference?!

Niet the Dark Absol · Accepted Answer · 2012-07-14 13:35:17Z

5

Like this:

usort($array,function($a,$b) {return $a['quantity']-$b['quantity'];});
return $array[0];

If needed, create a copy of the original array using $copy = array_slice($array,0);

answered Jul 14, 2012 at 13:35

Niet the Dark Absol

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Comments

Alex Ball · Accepted Answer · 2012-07-14 14:08:13Z

-1

For the min value:

$min = min(array_map("array_pop",$array));
print_r($min);

For the key:

$min = array_keys(array_map("array_pop",$array), min(array_map("array_pop",$array)));
print_r($min[0]);

edited Jul 14, 2012 at 14:08

answered Jul 14, 2012 at 13:59

Alex Ball

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2 Comments

Niet the Dark Absol Over a year ago

Causes E_STRICT errors: only variables should be passed by reference (ie. to array_pop). Additionally, your code relies on an associative array being in a specific order.

Alex Ball Over a year ago

@Kolink, aaahhhhh!!!!, I tried it on codepast only and initially seemed to work, we (I) never stop learning. Thanks for comment!

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