Access Javascript variables dynamically

Question

I know you might think this is a duplicate or a dumb question. But the answers doesn't help me.

Here's my simple problem:

var option1 = "some text";
var option2 = "some text";
var option3 = "some text";

I want to access the elements "option1, option2, option3" in a for loop:

for(var i = 1; i < 4; i++)
{
    alert(option+i);   
}

I know that it shouldn't be option+i but I dont know how to solve this.

Thanks for the help in advance.

If you find this to be a duplicate just mark this question. Thanks

Niet the Dark Absol · Accepted Answer · 2012-07-17 04:17:26Z

6

If they are variables in the window scope, then you can access window['option'+i]. However, you really should just use an array:

var option = [
    "some text",
    "option 2",
    "option 3"
];
for( var i=0; i<3; i++) alert(option[i]);

answered Jul 17, 2012 at 4:17

Niet the Dark Absol

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Comments

hsuk · Accepted Answer · 2012-07-17 04:22:02Z

1

Please try this one:

    option = new Array();
    option[1] = "some text";
    option[2] = "some text";
    option[3] = "some text";
    for(var i = 1; i < 4; i++)
    {
        alert(option[i]);   
    }

answered Jul 17, 2012 at 4:22

hsuk

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Comments

Moin Zaman · Accepted Answer · 2012-07-17 04:19:59Z

1

Try this:

var option1 = "some text";
var option2 = "some text";
var option3 = "some text";

for(var i = 1; i < 4; i++)
{
 alert(eval('option'+i) + '\n');
}

It's better if you try and use an array or access it via window as Kolink posted. And if you do use eval, make sure nothing that is not in your control gets eval'ed as its a security risk.

answered Jul 17, 2012 at 4:19

Moin Zaman

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Comments

Glenn Ferrie · Accepted Answer · 2012-07-17 04:17:17Z

0

change your loop to look like this:

for(var i = 1; i < 4; i++)
{
    alert(eval("option"+i));   
}

Let me know if you have any questions

answered Jul 17, 2012 at 4:17

Glenn Ferrie

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4 Comments

Niet the Dark Absol Over a year ago

I have a question: Are you crazy? This is probably the worst use of eval I have ever seen, and I've seen some pretty bad stuff...

approxiblue Over a year ago

It works, but... it rhymes with "evil." stackoverflow.com/questions/86513/…

Glenn Ferrie Over a year ago

@Kolink thank you for your feedback. This is a silly, simple problem to begin with. I upvoted your answer its a more fundamentally stable approach. I am not crazy

Abhishek Mehta Over a year ago

var x = ['text1','text2','text3']; for (var i =0; i< x.length; i++) { console.log(x[i]); }

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