PHP - Adding string value to associative array

Question

This seem so simple, and yet I can't find a solution anywhere.

What I want to do is add the contents (r-value) of a variable to an associative array instead of a reference to the variable.

For example, I want this:

$myStr1 = "sometext";
$myStr2 = "someothertext";

$myArray = array(
    "key1"=>$myStr1,
    "key2"=>$myStr2
);

echo($myArray["key1"]);

To produce this:

"sometext"

Instead of this:

"1"        // why??

Any help would be appreciated.

EDIT:

The above works; my bad. Here's the real problem - my $myStr1 variable isn't just assiged a string literal like in the above; it's created using the following syntax:

$myStr1 = "sometext" + anObject->intProperty + "moretext";

Basically I use the + to concatenate various types into a string. Maybe + isn't doing what I think it's doing?

EDIT:

It was definitely the + operator. I casted all non-strings to strings and used . to concatenate instead.

Crap. Well I guess I have some investigative work to do. Thanks for pointing this out. — Nathan Friend
– Nathan Friend, Commented Jul 19, 2012 at 2:12
For the record the + operator in PHP only performs additions, and if you use it with strings it will just try to cast the strings to values (1) and add them. (just in case it was still unclear) — Mahn
– Mahn, Commented Jul 19, 2012 at 3:20

SomeKittens · Accepted Answer · 2012-07-19 02:12:50Z

1

You've got it correct the first time. Try this:

$myStr1 = "sometext";
$myStr2 = "someothertext";

$myArray = array(
    "key1"=>$myStr1,
    "key2"=>$myStr2
);

unset($myStr1);

echo($myArray["key1"]);

Even though we unset() the $myStr1 variable, it still echoed sometext.

It should be noted that while it is possible to set $myStr1 by reference, it's not the default.

answered Jul 19, 2012 at 2:12

SomeKittens

39.6k19 gold badges117 silver badges145 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

uınbɐɥs Over a year ago

Your answer is the same as the other one, plus the comment.

zerkms Over a year ago

&"sometext"; - it's not valid php. Only variables can be passed by reference

SomeKittens Over a year ago

@ShaquinTrifonoff in other words, I provide an actual answer, instead of a comment in answer form?

SomeKittens Over a year ago

@zerkms noted, thanks. Momentary brain lapse. It's fixed now.

anhtuannd · Accepted Answer · 2012-07-19 02:09:55Z

0

Try your code and its result is:

sometext

answered Jul 19, 2012 at 2:09

anhtuannd

9729 silver badges17 bronze badges

1 Comment

zerkms Over a year ago

Even though this may be considered as an answer, I still personally think it would be more suitable to leave it as a comment

Collectives™ on Stack Overflow

PHP - Adding string value to associative array

2 Answers 2

4 Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

4 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related