How to find a url pattern in java using regex

Question

I want to find out if a given string (that represent a url) is from the same sub domain. For example, http://www.myDomain.com/someThing with the combination of myDomain.com will return true. So will the following:

http://myDomain.com; http://www.domain.myDomain.com;

But the next (illeagal) url will not - 'http://.myDomain.com' (note the dot before myDomain)

Basically, I need a regex that represent whatever before myDomain.com - which in general needs to be (http|https)://[a-z.]myDomain - which mean that just before myDomain.com there might be letters followed by dot (0 or more times) - but if there are no letters, there shouldn't be dot as well.

Does anyone know how to assemble that regex?

This might help stackoverflow.com/questions/1189128/…

mlishn
– mlishn

2012-07-24 16:20:15 +00:00
Commented Jul 24, 2012 at 16:20 — mlishn
– mlishn, Commented Jul 24, 2012 at 16:20

Mike Brant · Accepted Answer · 2012-07-24 16:19:45Z

1

http(s)?://([a-z]+\.)*myDomain\.com

answered Jul 24, 2012 at 16:19

Mike Brant

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Michael Besteck · Accepted Answer · 2012-07-24 16:35:58Z

It can be done with a combination of the URL class and a regular expression:

    String url = "myDomain.com";
    String[] urlTest = {
        "http://www.myDomain.com/someThing",
        "http://myDomain.com",
        "http://www.domain.myDomain.com",
        "http://.myDomain.com",
        "http://example.com"

    };
    for (String urlx : urlTest) {
        System.out.print(urlx + "\t");
        try {
            URL u = new URL(urlx);
            String host = u.getHost();
            System.out.print("HOST=" + host + "\t");
            Matcher m = Pattern.compile("(.+\\.)?myDomain\\.com").matcher(host);
            System.out.println(m.matches());

        } catch (MalformedURLException ex) {
            System.out.println("false (no valid url)");
        }
    }

Kul Bhushan Prasad · Accepted Answer · 2019-06-26 06:49:34Z

0

Putting example here:

Pattern aPattern = Pattern.compile("https://example.com[^\"<$\n \\[\\])]+", 
Pattern.MULTILINE);
            Matcher aMatcher = aPattern.matcher(Big String);
while (aMatcher.find()) {
logger.info(aMatcher.group());
}

answered Jun 26, 2019 at 6:49

Kul Bhushan Prasad

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