I've a progam installed in my linux box called my-scheduler-1.1.0-1112
When I do rpm -qa | grep my, it lists as shown below:
my-scheduler-1.1.0-1112
I want a command which will extract 1.1.0-1112 which is version part in my shell script.
what would be the command to extract it in shell script?
For this question you can try the --queryformat parameter for rpm.
like:
rpm -qa --queryformat '%{NAME}' | grep my
should print
my-scheduler
without the version string... What is much better as mugling it with sed or like. Because you can get something like package-1.0.3-rc2 or soo..
For version-release: use:
--queryformat "%{VERSION}-%{RELEASE}"
and maybe will be useful read http://www.rpm.org/max-rpm/ch-queryformat-tags.html - here is many useful query format tags, so you can directly can get what you want and in what format you want, without scripting...
Not sure what other version strings you may encounter, but you can try:
sed -e 's/^[^0-9]*-//g'
This is a sed replace. It's matching the regular expression ^[^0-9]*-, which is:
-And it replaces everything that matched with a blank, essentially removing it. This should leave everything after that which is the version string.
