Using results of php Query_String

Question

I had to add a query on the end of my URL, like this:

http://www.somewordpressite.com/?page_id=57?login=failed

Now I need to check if '?login=failed' exists, so I can load the correct piece of a template.

I have tried a bunch of variations, but I just can't seem to grab it.

<?php

$checkurlquery[] = $_SERVER['QUERY_STRING'];
//echo json_encode($_GET, JSON_HEX_TAG);

foreach($checkurlquery as $key => $v){
  $dice = $checkurlquery[$key];
  echo ($dice);
} 
?>

Result: page_id=57?login=failed

Ultimately, I'm just trying to get to here:

if ( //LOGIN failed )) {
        get_template_part( 'login', 'failed' );
} else {
    get_template_part( 'login', 'form' );
}

How can I check for login=failed, so I can use it to load the right template part? Thanks.

Edit: Yes, I was able to change the URL, so it can be: http://www.somewordpressite.com/?page_id=57&login=failed, but it created an issue. Because Wordpress uses that '?', then if I am on the home page, and fail at login, I get a 404 error:

This URL is ok and grabs the index page:
www.site.com/?login=failed

This URL is a 404 error:
www.site.com/&login=failed

Edit: Here is the updated function necessary in Wordpress functions.php: Redirect after login, Wordpress URLs

Then in header.php (or place of your choice), add:

 <?php

if(isset($_GET['login']) === true and $_GET['login'] === 'failed')
{
   get_template_part( 'login', 'failed' );
} else {
   get_template_part( 'login', 'form' );
}
?>

Your query is malformed ... there should be only one ?

Ja͢ck
– Ja͢ck

2012-08-17 05:23:24 +00:00
Commented Aug 17, 2012 at 5:23 — Ja͢ck
– Ja͢ck, Commented Aug 17, 2012 at 5:23

Musa · Accepted Answer · 2012-08-17 05:21:23Z

2

Can't you use a normal query string

http://www.somewordpressite.com/?page_id=57&login=failed

and use something like

if ($_GET['login'] == 'failed') {
        get_template_part( 'login', 'failed' );
} else {
    get_template_part( 'login', 'form' );
}

answered Aug 17, 2012 at 5:21

Musa

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2 Comments

You Qi Over a year ago

it's better to check with isset($_GET['login']) 1st or else you will get some funny warning.

Sammaye Over a year ago

@YouQi It's called an E_NOTICE and it is an error type of undefined index

Scuzzy · Accepted Answer · 2012-08-17 05:23:18Z

0

if you want to test for the query string parameters existence

if(isset($_GET['LOGIN']) === true)
{
 // it has at least been set
}

in addition if you also want to test for a specific value

if(isset($_GET['login']) === true and $_GET['login'] === 'failed')
{
 // it been set and it equals a specific value
}

answered Aug 17, 2012 at 5:23

Scuzzy

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6 Comments

Jen Over a year ago

What is the meaning of 3 equal signs, please? I hadn't seen that before.

dan-lee Over a year ago

Its a strict check if this equals exactly true and not a "truthy" value (like "1" or "string" which will be true too with 2 signs) but here its unnecessary, because isset only returns true or false, you can rely on that.

Jen Over a year ago

Edited my post, I checked and rechecked whether I could change my URL, and it creates an error because of how Wordpress is setup (I think), but there may be a fix that could be added if anyone knows Wordpress.

Jen Over a year ago

Should I ask that in a separate question? It's a common Wordpress issue, dissatisfaction with the login process.

Scuzzy Over a year ago

you might want get_query_var('login') instead of $_GET['login'] then

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