removing objects from an object array in php?

Question

for example say i have an object array called $list looks like this:

<(stdClass)#16 (3) {
  ["1"]=>
  <(8) "50504496"
  ["2"]=>
  <(8) "12435374"
  ["3"]=>
  <(8) "12436374"

Im doing a foreach on the object array and removing them if they exist in the database i.e

   foreach($list as $l){

    //do the query

    if( it exists){
      //remove from objects: this is where i need help!!
      }
   }

i have the db logic, im just stuck to know how i can remove objects, i was thinking maybe i should create a new object and add them thier. thanks }

unset php.net/unset

EaterOfCode
– EaterOfCode

2012-08-17 11:59:52 +00:00
Commented Aug 17, 2012 at 11:59 — EaterOfCode
– EaterOfCode, Commented Aug 17, 2012 at 11:59

mintobit · Accepted Answer · 2012-08-17 12:17:04Z

4

Use: unset

foreach($list as $key => $obj){
  if( exists .. ) {
      unset($list[$key]);
  }
}

edited Aug 17, 2012 at 12:17

mintobit

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answered Aug 17, 2012 at 12:00

Sudhir Bastakoti

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1 Comment

user1551482 Over a year ago

thanks brillant answer, what deos ... stand for is it 1,2 or 3 $var names

Gntem · Accepted Answer · 2012-08-17 12:01:29Z

0

run your query and if it returns >0 number of rows then you have a result, use unset($object->$var) to unset a variable

answered Aug 17, 2012 at 12:01

Gntem

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Comments

GautamD31 · Accepted Answer · 2012-08-17 12:04:25Z

0

Try like:

    foreach($list as $li)
    {
        if($li)
        {
            //copy into another array.
        }
    }

i thnk its may simple

answered Aug 17, 2012 at 12:04

GautamD31

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1 Comment

user1551482 Over a year ago

how can i copy into another array?

GautamD31 · Accepted Answer · 2012-08-17 12:37:50Z

0

Try like: $i=0;

  foreach($list as $li)
  {
      if($li)
      {
          $b[i] = $li;
          $i++;
      }
   }

array '$b' will hold the values in $list which are not null

answered Aug 17, 2012 at 12:37

GautamD31

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