This must be easy, but I can't figure how right now without using urllib module and manually fetching remote file
I want to overlay plot with remote image (let's say "http://matplotlib.sourceforge.net/_static/logo2.png"), and neither imshow() nor imread() can load the image.
Any ideas which function will allow loading remote image?
It is easy indeed:
import urllib2
import matplotlib.pyplot as plt
# create a file-like object from the url
f = urllib2.urlopen("http://matplotlib.sourceforge.net/_static/logo2.png")
# read the image file in a numpy array
a = plt.imread(f)
plt.imshow(a)
plt.show()
urllib instead of urllib2 and call urllib.request.urlopen instead of urllib2.urlopen.This works for me in a notebook with python 3.5:
from skimage import io
import matplotlib.pyplot as plt
image = io.imread(url)
plt.imshow(image)
plt.show()
ValueError: invalid PNG header for the urllib2 solution but this worked well for mepip install scikit-image
you can do it with this code;
from matplotlib import pyplot as plt
a = plt.imread("http://matplotlib.sourceforge.net/_static/logo2.png")
plt.imshow(a)
plt.show()
URLError: <urlopen error unknown url type: s3>
np.array(PIL.Image.open(urllib.request.urlopen(url)))pyplot.imread for URLs is deprecated
Passing a URL is deprecated. Please open the URL for reading and pass the result to Pillow, e.g. with np.array(PIL.Image.open(urllib.request.urlopen(url))).
Matplotlib suggests using PIL instead. I prefer using imageio as sugested by SciPy:
imread is deprecated in SciPy 1.0.0, and will be removed in 1.2.0. Use imageio.imread instead.
imageio.imread(uri, format=None, **kwargs)
Reads an image from the specified file. Returns a numpy array, which comes with a dict of meta data at its ‘meta’ attribute.
Note that the image data is returned as-is, and may not always have a dtype of uint8 (and thus may differ from what e.g. PIL returns).
Example:
import matplotlib.pyplot as plt
from imageio import imread
url = "http://matplotlib.sourceforge.net/_static/logo2.png"
img = imread(url)
plt.imshow(img)
