I have a String like this:
http://www.fam.com/FAM#Bruno12/06/2011
How can I cut http://www.fam.com/FAM# and 12/06/2011 in order to get only Bruno.
The format is always:
http://www.fam.com/FAM#NAMEDATE
Is there a simple way to do this? Can you just explain me how?
Simply do this:
myString = original.substring(23, original.length() - 10);
23 is for http://www.fam.com/FAM#original.length() - 10 is for 12/06/2011Use :
String str = "http://www.fam.com/FAM#Bruno12/06/2011";
String[] arr = str.split("#|[\\d+/]"); // last index of arr is Bruno
If the string always starts with http://www.fam.com/FAM# then it's simple: that's 23 characters, so take the substring from position 23 (note that indices are zero-based).
String input = "http://www.fam.com/FAM#Bruno12/06/2011";
String result = input.substring(23);
If you want everything after the first # in the string, then search for # and take everything that comes after it:
int index = input.indexOf('#');
String result = input.substring(index + 1);
(error checking omitted for simplicity).
To remove the date, remove the last 10 characters.
See the API documentation of class String for useful methods.
use regex #(.*?)\\d\\d/ to capture it.
You should use standard URL parsing code, as at Could you share a link to an URL parsing implementation?
I expect the URL parser can cope with the fact that your Ref (i.e. "Bruno12/06/2011") contains slashes.
URL url = new URL(inputString);
String nameDate = url.getRef();
expresses what you want to do in the simplest and clearest form.
