I have a String with the value of something like so: "H798asdhka80:124htg"
I want to retrieve from this string (and similarly structured strings) every character before the colon ":" so my new string would look like this: H798asdhka80
What would the code to do this look like?
Thanks
use
var str="H798asdhka80:124htg".split(':')[0]
Using split(':') you get the array ["H798asdhka80","124htg"]. And then use only the first element of that array.
Use substr:
var str = "H798asdhka80:124htg",
strpart = str.substr(0,str.indexOf(':'));
or slice
var str = "H798asdhka80:124htg",
strpart = str.slice(0,str.indexOf(':'));
or split
var strpart = "H798asdhka80:124htg".split(/:/)[0];
or match
var str = "H798asdhka80:124htg".match(/(^.+)?:/)[1];
or replace
var str = "H798asdhka80:124htg".replace(/:.+$/,'');
or create a more generic String.prototype extension
String.prototype.sliceUntil = function(str){
var pos = this.indexOf(str);
return this.slice(0, (pos>-1 ? pos : this.length));
}
var str = "H798asdhka80:124htg".sliceUntil(':124');
A reg exp answer, match anything from the start of the string to the colon.
var str = "H798asdhka80:124htg";
var txt = str.match(/^[^:]+/);
"H798asdhka80:124htg".split(':')[0]
You don't really need a RegExp for this. This should work for you:
str.split(':')[0];
Anyway, the other way would be to replace the unneeded part of the string with a regular expression, like this:
str.replace(/:.+$/, '');