Consider:
var dummyArray = [{
"fname": "gali",
"lname": "doe"
}, {
"fname": "john",
"lname": "danny"
}, {
"fname": "joe",
"lname": "dawns"
}, {
"fname": "liji",
"lname": "hawk"
}]
dummyArray = j$.grep(dummyArray, function(dt) {
return (dt.fname== 'j');
});
How can I query the "fname" which contains letter "j" using the grep function?
Using the ECMAScript 5 standard function Array.filter to only return the elements matching the predicate:
Starting with "j"
var j = dummyArray.filter(function(o) {
return o.fname.charAt(0) === 'j';
});
or, containing "j"
var j = dummyArray.filter(function(o) {
return o.fname.indexOf('j') >= 0;
});
You can use indexOf:
dummyArray = $.grep(dummyArray, function(dt) {
return dt.fname.indexOf("j") != -1;
});
You can do this with vanilla JavaScript like so:
dummyArray = (function(){
var result = [];
for (var i=0, l=dummyArray.length; i<l; i++)
if (/j/.test(dummyArray[i].fname))
result.push(dummyArray[i]);
return result;
}());
You can easily test stuff by changing the regex. For example, you could test for names that start by j instead of contain with /^j/.
$.grep and Array.filter ?You can use the index of function:
dummyArray = $.grep(dummyArray, function(dt) {
return dt.fname.indexOf("j") != -1;
});
// To be case-insensitive, use:
dummyArray = $.grep(dummyArray, function(dt) {
return dt.fname.toLowerCase().indexOf("j") != -1;
});
Fiddle: http://jsfiddle.net/kYXPa/
filterto find ALL, andfindto find first, orsometo check if it exist at all) they returns: array, one, bool respetively