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I have $view_data['auth_info'] which is populated with a query row, that works fine. But i need to add an additional row to this array. How is this possible? All the variables are unique, so theres no change i will have to identical definitions.

I tried following:

$view_data['auth_info'] = $myFirstSQLRow
array_push($view_data['auth_info'],$mySecondSQLRow);

But it failed:

Message: array_push() [function.array-push]: First argument should be an array

But isnt the first var an array or have i misunderstood something?

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  • $view_data['auth_info'] = array($myFirstSQLRow, $mySecondSQLRow)? Commented Sep 25, 2012 at 19:58
  • I want to merge the two variables into one spot. If you understand. Commented Sep 25, 2012 at 20:00
  • 1
    Very hard to understand what you mean by 'merge'. Can you give an example? Commented Sep 25, 2012 at 20:03
  • @Aust, tried to give an example on this merging, which is exactly what i need. Commented Sep 25, 2012 at 20:52

1 Answer 1

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You are looking for array_merge. Use it like this:

$view_data['auth_info'] = $myFirstSQLRow;
$view_data['auth_info'] = array_merge($view_data['auth_info'], $mySecondSQLRow);

As it says in the documentation, you may need to type-cast (by putting (array) in front of your variables.)

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7 Comments

I tried this, also by typecasting both vars to (array), but when i try to print the variables $view_data['auth_info']->name i get Message: Undefined offset: 1 and Trying to get property of non-object
@JavaCake - Try this instead: $view_data['auth_info']['name']
Works like a charm. But isnt there a workaround so i still can use the objects rather than typecasting to array?
@JavaCake - I dunno. Sorry, I've never had to do that. But out of curiosity, why do you need to do that?
Im querying data from two tables and returning them as rows. I wanted to merge the two rows somehow.
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