Processing a dynamically generated form in javascript with php post to database

Your jQuery code is already explicitly naming the fields. Eg:

$("<input>").attr("name", "a").appendTo(newDiv);

This will create an input named a:

<input name="a" />

Your jQuery gives each dynamically created input the same name. If you submit the following form with 3 fields having the same name, the server would receive a=value1&a=value2&a=value3.

<form>
    <input name="a" value="value1" />
    <input name="a" value="value2" />
    <input name="a" value="value3" />
    <input type="submit" />
</form>

This works with most server technologies, but not with PHP. PHP overwrites existing values with the last value. So, if you examined the value of a in PHP, you would only see value3. But, the good news is that you can change your input names slightly and have PHP recognize all the values. In PHP, when you append square brackets to your input names (name="a" becomes name="a[]"), PHP parses the values into an Array. So for the following slightly modified form:

<form>
    <input name="a[]" value="value1" />
    <input name="a[]" value="value2" />
    <input name="a[]" value="value3" />
    <input type="submit" />
</form>

When you look at the value of a in PHP, you will get an array of values containing value1, value2, and value3. So, just change your jQuery code to use square brackets at the end of the name:

$("<input>").attr("name", "a[]").appendTo(newDiv);