string array error while compiling

Question

This is my sample code:

#include <iostream>
#include <cstring>
#include <vector>
#include <iterator>
#include "MQmessage.h"

using namespace std;

int main()
{
    // declaring an array to store name/value pair
    struct Property  user_property[15];
    const char* const list[] = {"stateCode","errorCode"};
    const size_t len = sizeof(list) / sizeof(list[0]);
    for (size_t i = 0; i < len; ++i) {
        strcpy(user_property[0].name,list[i]);
    }
    for (size_t i = 0; i < len; ++i) {
        std::cout<<user_property[i]<<endl;
    }
    return 0;
}

I am getting follwoing errors in the code:

no match for 'operator<<' in std::cout

Can someone tell me what is that I am doing wrong?

The main problem is as described by the answers below, but as an aside note: In the strcpy call you refer to user_property[0] independent of the value of i. Also, there are always 15 Property objects, independent of len. Finally, I hope the constructor of Property allocates sufficient space in name for the strcpy to work without problems. — jogojapan
– jogojapan, Commented Oct 9, 2012 at 7:12

Marcus · Accepted Answer · 2012-10-09 07:04:29Z

3

I guess you want std::cout<<user_property[i].name<<endl, otherwise you'll have to overload the << operator of Property.

answered Oct 9, 2012 at 7:04

Marcus

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Comments

Maksim Skurydzin · Accepted Answer · 2012-10-09 07:04:01Z

1

You need to overload operator<< for struct Property.

Please note, that if you want to output just Property::name and it is std::string you also need to #include <string> to make operator<< for std::string available.

answered Oct 9, 2012 at 7:04

Maksim Skurydzin

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1 Comment

Open AI - Opting Out Over a year ago

If std::string is a member of Property the header will already be included. However, they're using strcpy so it probably isn't a std::string.

Karen Tsirunyan · Accepted Answer · 2012-10-09 07:21:05Z

0

Just add a printing function for the "Property" like this one :

void print()
{
    std::cout<<this->name<<endl;
    std::cout<<this->othermember<<endl;  //if you have some other members
}

and in your main just do the following:

for (size_t i = 0; i < len; ++i) {
    user_property[i].print(); }

answered Oct 9, 2012 at 7:21

Karen Tsirunyan

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