Array of strings (char array) in C (Arduino). How do I accomplish it?

Question

I want to access certain data which basically looks like this:

char* a[]={
    "0000000000",
    "0000000000",
    "0011111100",
    "0000100100",
    "0000100100",
    "0011111100",
    "0000000000",
    "0000000000",
};

I have around 200 of those data sets and want to access it in the way.

fooBar[23]; --> This should return the 23rd character array (which looks like the example listed above).

As far as I understand from my other programming knowledge, I would need an array of Strings. The array index is my lookup number (which will be a maximum of 255). The array values are the character arrays as shown above.

How can this be accomplished with C (Arduino IDE)?

You've already shown the solution to your question. So what is unclear about that? — Olaf Dietsche
– Olaf Dietsche, Commented Oct 17, 2012 at 9:32
Note that fooBar[23] is actually the 24th character array. I know nothing about arduino and what restrictions it places on the use of C but the proposed array is correct (maybe change type to const char* as string literals should not be modified). — hmjd
– hmjd, Commented Oct 17, 2012 at 9:37
to make it more clear: i need an array of the example array construct. — z3cko
– z3cko, Commented Oct 17, 2012 at 9:46

Peter Mortensen · Accepted Answer · 2012-10-17 23:53:27Z

4

Just use a two dimensional array. Like:

char a[][]={
    "0000000000",
    "0000000000",
    "0011111100",
    "0000100100",
    "0000100100",
    "0011111100",
    "0000000000",
    "0000000000",
};

edited Oct 17, 2012 at 23:53

Peter Mortensen

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answered Oct 17, 2012 at 12:28

taufique

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Comments

hmjd · Accepted Answer · 2012-10-17 10:13:04Z

2

Based on your comment, I think this is what you are asking for:

const char* data_sets[][200] =
    {
        { "00000", "11111",         },
        { "22222", "33333", "44444" },
        { "55555"                   },
    };

Each entry in data_sets is an array of 200 const char*. For accessing:

for (size_t i = 0; i < sizeof(data_sets) / sizeof(data_sets[0]); i++)
{
    const char** data_set = data_sets[i];
    printf("data_set[%u]\n", i);
    for (size_t j = 0; data_set[j]; j++)
    {
        printf("  [%s]\n", data_set[j]);
    }
}

See online demo at http://ideone.com/6kq2M.

answered Oct 17, 2012 at 10:13

hmjd

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