Check if an array contains another array with PHP [duplicate]

Question

Possible Duplicate:
Checking if an array contains all elements of another array

I have posted something like this to the Stackoverflow before, but the answers do not fully satisfy me. That's why I'm posting the question again, but changing the question all along.

Some people helped me to construct a function that checks if an array($GroupOfEight[$i]) that is an element of a multidimensional array($GroupOfEight) equals another array($stackArray), disregarding the number ordering in the arrays.

However, what I need to check is whether the mentioned array($stackArray) contains any another array($GroupOfEight[$i]) in the multidimensional array($GroupOfEight) or not, that means main array($stackArray) can consist more elements than subarrays($GroupOfEight[$i]).

Here is the one working code that I've gathered so far, but need to be modified to the version I want:

 <?php
    $GroupOfEight = array (
                          array(0,1,3,2,4,5,7,6),
                          array(4,5,6,7,15,12,13,14),
                          array(12,13,15,14,8,9,11,10),
                          array(2,6,14,10,3,7,15,11),
                          array(1,3,5,7,13,15,9,11),
                          array(0,4,12,8,1,5,13,9),
                          array(0,1,3,2,8,9,11,10)
                );


    $stackArray = array(0,4,12,1,9,8,5,13,9,2,5,2,10);
    /*$stackArray gets value with POST Method by URL parameter.
    This is just the example. As you see this array contains 
    $GroupOfEight[4], and also it contains many other numbers.*/


    /* The function given below checks if $stackArray equals any
    of the subarrays of $GroupOfEight. However, we want to check
    if $stackArray caontains any of the subarrays of function.
    If it does, function should return the index number, if it
    doesnt it should return -1.*/
    function searcheight($stackArray,$GroupOfEight){
        for($i=0; $i<count($GroupOfEight);$i++){


  $containsSearch = (count(array_intersect($stackArray,$GroupOfEight[$i])) == count($stackArray) && count(array_intersect($stackArray,$GroupOfEight[$i])) == count($GroupOfEight[$i]));
        if($containsSearch){
            return $i; //This specifies which index in GroupOfEight contains a matching array
        }
    }
    return -1;
}

// Calling the function that is given above.
echo searcheight($stackArray,$GroupOfEight);
?>

Any logical ideas or solutions will kindly be much appreciated. Thanks.

For the assumed $stackArray, it should give 4, which is the index of the contained subarray index number in $GroupOfEight — mozcelikors
– mozcelikors, Commented Oct 17, 2012 at 14:57
4 is array(1,3,5,7,13,15,9,11) and $stackArray = array(0,4,12,1,9,8,5,13,9,2,5,2,10); .. can't you see 3 is missing in the list ??? — Baba
– Baba, Commented Oct 17, 2012 at 14:59
oh yes, but you got the idea. it contains a subarray and other elements. i gotta find which one it contains, or does it not. — mozcelikors
– mozcelikors, Commented Oct 17, 2012 at 15:00

Marcin Orlowski · Accepted Answer · 2012-10-17 14:53:44Z

9

This one is fast:

function contains_array($array){
    foreach($array as $value){
        if(is_array($value)) {
          return true;
        }
    }
    return false;
}

edited Oct 17, 2012 at 14:53

Marcin Orlowski

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answered Oct 17, 2012 at 14:51

Adder

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4 Comments

Marcin Orlowski Over a year ago

always use block brackets {}, even for oneliners like yours return true;. It's good habit that pays of whenever you jump into languages using preprocessor and macros...

Shawn Wernig Over a year ago

You can use a FOR loop, and return the counter if you need the position of the array. Or, instead of returning true, return the array key $array.

mozcelikors Over a year ago

I dont think this one does exactly what i asked for, thanks though

mickmackusa Over a year ago

I agree with @moz This is the correct answer to a different question. I have no idea why this has so many UVs.

Baba · Accepted Answer · 2012-10-17 15:21:35Z

3

You can try

$GroupOfEight = array(
        array(0,1,3,2,4,5,7,6),
        array(4,5,6,7,15,12,13,14),
        array(12,13,15,14,8,9,11,10),
        array(2,6,14,10,3,7,15,11),
        array(1,3,5,7,13,15,9,11),
        array(0,4,12,8,1,5,13,9),
        array(0,1,3,2,8,9,11,10));

$stackArray = array(0,4,12,1,9,8,5,13,9,2,5,2,10);

function searcheight($stackArray, $GroupOfEight) {
    $list = array();
    for($i = 0; $i < count($GroupOfEight); $i ++) {
        $intercept = array_intersect($GroupOfEight[$i], $stackArray);
        $len = count($intercept);
        if ($len % 4 == 0) {
            $list[$i] = $len;
        }
    }
    arsort($list);
    if (empty($list))
        return - 1;
    return key($list);
}
echo searcheight($stackArray, $GroupOfEight);

Output

answered Oct 17, 2012 at 15:21

Baba

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3 Comments

mozcelikors Over a year ago

Baba, I've made modification functions and I've moved to 4 group elimination. Please revise this code and tell where i am wrong. ($GroupOfFour has 16mem) function searchFourTerms($leftArray, $GroupOfFour) { $len4 = count($leftArray); $list4 = array(); for($i4 = 0; $i4 < count($GroupOfFour); $i4 ++) { $intercept4 = array_intersect($GroupOfFour[$i4], $leftArray); $len4 = count($intercept4); if (count($intercept4) % 4 == 0) { $list4[$i4] = $len4; } } arsort($list4); if (empty($list4)) return - 1; return key($list4); }

mozcelikors Over a year ago

I think I solved it, but still got some issues. Please move this to chat when you're here.

mickmackusa Over a year ago

This answer is unexplained and the other answer (with 12 UVs) is 100% wrong. This page is thus low-value to researchers.

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