PHP not recognising AJAX call

Question

I'm calling a file via jQuery's AJAX method looks like this:

    $is_ajax = $_REQUEST['is_ajax'];
    if(isset($is_ajax) && $is_ajax)
    {
        echo 'its ajax!';
    }
    else echo 'im called, but not via ajax';

and my AJAX call:

jQuery.ajax({
                type: 'POST',
                url: 'my-service.php',
                data: data,
                success: function(response) { 
                    alert(response);
                 }
            });

But alert always shows 'not ajax' message. What am I doing wrong?

Oh my dear, I forgot to include is_ajax: 1 in data being sent. Too many hours in code right now... — Josip Codes
– Josip Codes, Commented Oct 23, 2012 at 10:11
you want to read this[api.jquery.com/jQuery.ajax/] ,here many samples, for used Ajax with Jquery, I thinks, Lex, and Muthu are the response, you want to define is_ajax value, in your Ajax's request... — Doc Roms
– Doc Roms, Commented Oct 23, 2012 at 10:15

BenjaminRH · Accepted Answer · 2012-10-23 10:39:43Z

3

It seems that your method of detecting AJAX is wrong. If your server supports HTTP_X_REQUESTED_WITH, then it's the way to go :

if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
  /* special ajax here */
  die($content);
}

source : Detect an AJAX Request

edited Oct 23, 2012 at 10:39

BenjaminRH

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answered Oct 23, 2012 at 10:15

max collomb

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Comments

Josip Codes · Accepted Answer · 2012-10-23 10:12:26Z

2

Needed to add is_ajax: 1 in data that is being sent via AJAX call.

answered Oct 23, 2012 at 10:12

Josip Codes

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1 Comment

Peon Over a year ago

I think @Florent should repost this for the answer

jadoux · Accepted Answer · 2012-10-23 10:12:56Z

2

try this :

jQuery.ajax({
            type: 'POST',
            url: 'my-service.php',
            data: {is_ajax:1},
            success: function(response) { 
                alert(response);
             }
        });

answered Oct 23, 2012 at 10:12

jadoux

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Comments

Muthu Kumaran · Accepted Answer · 2012-10-23 10:12:08Z

1

Another method

You can simple check whether the request is AJAX or not like this,

/* AJAX check  */
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
  echo 'its ajax!';
}else{
  echo 'im called, but not via ajax';
}

answered Oct 23, 2012 at 10:12

Muthu Kumaran

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1 Comment

John Dvorak Over a year ago

Who is setting the HTTP header? I wouldn't trust IE8 to insert this header.

donald123 · Accepted Answer · 2012-10-23 10:13:08Z

1

edit your AJAX call and modify the data

jQuery.ajax({
            type: 'POST',
            url: 'my-service.php',
            data: {"is_ajax":"the value"},
            success: function(response) { 
                alert(response);
             }
        });

answered Oct 23, 2012 at 10:13

donald123

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Comments

WomenInTech · Accepted Answer · 2012-10-23 10:14:03Z

1

Try this :

if(isset($_POST['is_ajax']))
{
    echo 'its ajax!';
}
else 
{
echo 'im called, but not via ajax';
}

answered Oct 23, 2012 at 10:14

WomenInTech

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4 Comments

WomenInTech Over a year ago

@jan dvorak : y dont you answer then instead of commenting on every answer !!

Memos Electron Over a year ago

@JanDvorak sufficient on what? they using more complex way. _POST is the standard way to receive on Ajax method.

John Dvorak Over a year ago

@memosdp OP was using $_REQUEST, which is a valid way to access POST variables. OP was missing the POST variable he was testing. This answer does not add the variable, only tests it in a different way./

Memos Electron Over a year ago

@JanDvorak i misunderstood that you said about sufficiency ... it was for the sufficiency like an answer ... took me a while to realize it ... despite this not worths a downvote ... as you want

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